Here's an example...
So, in our last example...
In the point ( -2, -1 ), x1 = -2 and y1 = -1 ... and, in the point ( 4, 3 ), x2 = 3 and y2 = 3
m = ( y2 - y1 ) / ( x2 - x1 ) = ( 3 - ( -1 ) ) / ( 4 - ( -2 ) ) = 4 / 6 = 2 / 3
But, notice something cool...
The order of the points doesn't matter! Let's switch them and see what we get:
In the point ( 4, 3 ), x1 = 4 and y1 = 3 ... and, in the point ( -2, -1 ), x2 = -2 and y2 = -1
m = ( y2 - y1 ) / ( x2 - x1 ) = ( -1 - 3 ) / ( -2 - 4 ) = -4 / -6 = 2 / 3 ... Same thing!
Let's try our new formula with the second example in the last lesson:
It was a line passing through
( -1, 4 ) and ( 2, -2 )
m = ( y2 - y1 ) / ( x2 - x1 ) = ( -2 - 4 ) / ( 2 - ( -1 ) ) = -6 / 3 = -2
The distributive property: a(b + c) = ab + ac
127 × 32 = 127 × (30 + 2) = 127 × 30 + 127 × 2 = (130 - 3) × 30 + (130 - 3) × 2
=(130)(30) - (3)(30) + (130)(2) - (3)(2) = 3900 - 90 + 260 - 6
= 3810 + 254 = 4064
127 × 32 = (130 - 3) × 32 = 130 × 32 - 3 × 32 = 130 × (30 + 2) - 96
= (130)(30) + (130)(2) - 96 = 3900 + 260 - (100 - 4) = 4160 - 100 + 4
= 4060 + 4 = 4064
Answer:
sorry hindi ako nakahabol
5*3=15
15-4= 11
hope I helped:)
