The change in internal energy of the combustion of biphenyl in Kj is calculated as follows
=heat capacity of bomb calorimeter x delta T where delta T is change in temperature
delta T = 29.4 -25.8= 3.6 c
= 5.86 kj/c x 3.6 c = 21.096 kj
Barium-131's radiation level won't reach 1/4 of its initial level for 24 hours.
ln[A] t = -kt + ln[A] 0 is the integrated rate rule for the first-order reaction A's products.
A straight line is produced when the natural log of [A] is plotted as a function of time since this equation has the form y = mx + b.
How is the length of a half-life determined?
The amount of time needed for the reactant concentration to drop to half its initial value is known as the half-life of a reaction. A first-order reaction's half-life is a constant that is correlated with its rate constant:
t 1/2 = 0.693/k.
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I believe it would be the last one because you can use the molar mass of HCl to find the number of moles, then use Avogadro’s number to find the number of atoms
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Letter A is the characteristic of all chemical change
Answer: The pentose phosphate pathway (PPP) is localized to the cytosol because fatty acid synthesis uses the NADPH generated by the PPP.
Explanation:
The pentose phosphate pathway is mainly catabolic and provides an alternative glucose oxidizing pathway for the generation of NADPH that is required for reductive biosynthetic reactions such as those of cholesterol biosynthesis, bile acid synthesis, steroid hormone biosynthesis, and fatty acid synthesis.
Fatty acid biosynthesis occurs in the cytosol and requires the reducing equivalent NADPH in large amounts. <em>The main source of generating NADPH in animal cells, the pentose phosphate pathway is therefore, localized in the cytosol in order to furnish a strongly reducing environment for fatty acid biosynthesis to proceed.</em>
