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3 years ago

MAGNESIO + OXIGENO nombre formula

Chemistry

1 answer:

jasenka [17]3 years ago

3 0

Answer:

Óxido de magnesio

Concepto:Es un óxido metálico, formado por magnesio y oxígeno, de estructura iónica cuya fórmula química es MgO.

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Ronaldo experimentally determined the

Yuri [45]

Answer:

Explanation:

%error= error/actual density x100

0.050/0.890 x100

=5.62%

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3 years ago

What state of matter has a fixed amount of volume but can change shapes according to its container?

valkas [14]

Yes, it is a liquid because a solid is a state of matter with a fixed volume and shape; and Gases take both the shape and the volume of their container; and liquid is the one that takes the shape of their container but not necessarily the volume.

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3 years ago

When a 0.235-g sample of benzoic acid is combusted in a bomb calorimeter, the temperature rises 1.643 ∘C . When a 0.275-g sample

andrew-mc [135]

Answer : The heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

Explanation :

First we have to calculate the specific heat calorimeter.

Formula used :

$Q=m\times c\times \Delta T$

where,

Q = heat of combustion of benzoic acid = 26.38 kJ/g = 26380 J/g

m = mass of benzoic acid = 0.235 g

c = specific heat of calorimeter = ?

$\Delta T$ = change in temperature = $1.643^oC$

Now put all the given value in the above formula, we get:

$26380J/g=0.235g\times c\times 1.643^oC$

$c=68323.38J/^oC$

Thus, the specific heat of calorimeter is $68323.38J/^oC$

Now we have to calculate the heat of combustion of caffeine.

Formula used :

$Q=c\times \Delta T$

where,

Q = heat of combustion of caffeine = ?

c = specific heat of calorimeter = $68323.38J/^oC$

$\Delta T$ = change in temperature = $1.584^oC$

Now put all the given value in the above formula, we get:

$Q=68323.38J/^oC\times 1.584^oC$

$Q=108224.23J=108.2kJ$

Now we have to calculate the moles of caffeine.

$\text{Moles of caffeine}=\frac{\text{Mass of caffeine}}{\text{Molar mass of caffeine}}$

Mass of caffeine = 0.275 g

Molar mass of caffeine = 194.19 g/mole

$\text{Moles of caffeine}=\frac{0.275g}{194.19g/mole}=0.00142mol$

Now we have to calculate the heat of combustion per mole of caffeine at constant volume.

$\text{Heat of combustion per mole of caffeine}=\frac{108.2kJ}{0.00142mol}=76197.18kJ/mole$

Therefore, the heat of combustion per mole of caffeine at constant volume is 76197.18 kJ/mole

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3 years ago

Cell Walls Function (short)

bazaltina [42]

The main functions of the cell wall are to provide structure, support, and protection for the cell.

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4 years ago

Is it a physical or a chemical change?

tatiyna

Answer:

Number 4 should be physical change since scientists are breaking the water into 2 elements, O₂ and H₂

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3 years ago