The reaction equation:
2Li + O → Li₂O
Molar ratio of Li to Li₂O is:
2 : 1
So if 3.03 moles of Li are present:
2/1 = 3.03 / x
x = 1.515 moles of Li₂O will be produced.
Hello! Let me try to answer this :)
Thanks and please correct if there are any mistakes ^ ^
Answer:
Ratio is 1:1
Explanation:
I do not see any coefficients infront of the reactants and the products, therefore, we can automatically assume that every reactant and product is 1 mole. Don't get confused by the 4 off the O. It just means that 1 mole of sulfate has 1 zinc and 4 oxygens.
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