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marin [14]
3 years ago
7

Please help me with this:

Mathematics
1 answer:
spayn [35]3 years ago
4 0

Answer:

Step-by-step explanation:

one way to describe  the prime version  of ABCD is that the sides are all 3 times that of the non- prime version.  So they are when scaled by 3 .. the same.

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Please help!!!<br> If h(x)= -3x-10, find h(-3)<br> Please give an explanation too. Thank you.
dalvyx [7]

Answer:

h(-3)=-1

Step-by-step explanation:

Replace all x in h(x)= -3x-10 by -3:

h(-3)=-3(-3)-10

Now multiply -3 and -3:

h(-3)=9-10

Simplify 9 and -10 (aka add 9 and -10 together):

h(-3)=-1

Answer: h(-3)=-1

Hope this helps!

5 0
3 years ago
Read 2 more answers
Simplify these equations 8y+2+3y-5
Alex777 [14]
The answe to this equation is 11y-3
5 0
3 years ago
Straight line AB is perpendicular to the straight line joining p(-6,-9) and Q(3,-12). Find the gradient of AB
PIT_PIT [208]
Yes the answer for it is -1/3
3 0
3 years ago
a piece of ribbon that is 2/3 of a yard long is to be cut into 1/12 yard pieces. How many pieces will there be?
Darina [25.2K]
Length of the original ribbon = 2/3 yard
Length of the ribbon in which the actual ribbon has to be cut = 1/12 yards
The above information's are already given in the question. It is required to find the number of pieces that the ribbon can be cut with the length that is already mentioned.
Then
Number of pieces that will be there = (2/3)/(1/12)
                                                         = (2 * 12)/3
                                                         = 24/3
                                                         = 8
So the actual ribbon can be cut into 8 pieces and each piece will have a length of 1/12 yards. Hopefully the procedure for doing this problem is clear to you. this is the easiest method for attempting these kind of problems.
3 0
3 years ago
Simplify completely.
Arte-miy333 [17]

Answer:

\large\boxed{\sqrt{27y^8}=3y^4\sqrt3}

Step-by-step explanation:

\sqrt{27y^8}=\sqrt{9\cdot3\cdot y^{4\cdot2}}\\\\\text{Use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b},\ (a^n)^m=a^{nm}\ \text{and}\ \sqrt{a^2}=a\\\\=\sqrt9\cdot\sqrt3\cdot\sqrt{(y^4)^2}=3\cdot\sqrt3\cdot y^4=3y^4\sqrt3

3 0
3 years ago
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