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2 years ago

Can someone help me please?

Mathematics

1 answer:

mafiozo [28]2 years ago

4 0

Answer:

1. The mathemagician is speaking

2. It says his name then puts a ":" than he talks

3. By the way he is speaking to Azaz, you can tell he disagrees with Azaz on something

4. I don't think I would because it seems he tries to force his opinions on people in a negative way. But that is a personal choice.

Step-by-step explanation:

Hope this Helped you :)

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For solving this question, you should apply the Population Growth Equation.

<h3>Population Growth Equation</h3>

The formula for the Population Growth Equation is:

$P_f=P_o*(1+\frac{R}{100} )^t$

Pf= future population

Po=initial population

r=growth rate

t= time (years)

STEP 1 - Find the constant rate of continuous growth, k, for this population.

For this exercise, you have:

Pf= future population= 185,000 in 2020.

Po=initial population =150,000 in 2010.

r=growth rate= ?

t= time (years)=2020-2010=10

Then,

$P_f=P_o*(1+\frac{R}{100} )^t\\ \\ 185000=150000\cdot \left(1+\frac{R}{100}\:\right)^{10}\\ \\ \left(1+\frac{R}{100}\right)^{10}=\frac{185000}{150000} \\ \\ \left(1+\frac{R}{100}\right)^{10}=\frac{37}{30}\\ \\ R=100\sqrt[10]{\frac{37}{30}}-100=2.11935\%$

STEP 2 - Find the <em>t</em> for population 250,000 people.

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Read more about the population growth equation here:

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