It’s 25 bc every 2 it goes up 5 dollars
If you start with a 12x16 rectangle and cut square with side length x, when you bend the sides you'll have an inner rectangle with sides
and
, and a height of x.
So, the volume will be given by the product of the dimensions, i.e.

The derivative of this function is

and it equals zero if and only if

If we evaluate the volume function at these points, we have

So, the maximum volume is given if you cut a square with side length

Answer:
33.3333333333
Step-by-step explanation:
One coin would equal over 11 more would be 8.3333333333 so time that by 4
GoodLuck
The equation that models this situation is z = 7.9y + 12.
A linear equation is a function that has a single variable raised to the power of 1. An example is x = 4y + 2.
Where:
- 2 is the constant
- x = dependent variable
- y = independent variable
From the equation given, 12 would be the constant, the independent variable would be 7.9 and z would be the dependent variable.
z = 7.9y + 12
Here is the complete question: A barrel of oil was filled at a constant rate of 7.9 gal/min. The barrel had 12 gallons before filling began. write an equation in standard form to model the linear situation.
A similar question was answered here: brainly.com/question/2238405
The distance from the sun is option 2 5.59 astronomical units.
Step-by-step explanation:
Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.
Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power
is on the variable we need to find so we multiply both the sides by an exponential power of
to be able to calculate 'a'.
P =
,
=
,
= a,
= a = 5.58533 astronomical units.
Rounding it over to nearest hundredth we get 5.59 astronomical units.