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Nataliya [291]
3 years ago
14

The answer to the picture please

Mathematics
1 answer:
Vinil7 [7]3 years ago
8 0

the required ans is 3√b+b/3b

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What are the solutions to this quadratic equation x2+6x-5=0
marishachu [46]

Answer:

See Below.

Explanation:

Quadratic Form:

a {x}^{2}  + bx + c

Quadratic Formula:

x =  \frac{ - b +   -  \sqrt{ {b}^{2}  - 4ac} }{2a}

Based on the information given from the question, we can deduce:

a = 1

b = 6

c = -5

Now we can substitute all these values into the formula to find x.

x =   \frac{ - 6 +  -  \sqrt{ {6}^{2}  - 4(1)( - 5)} }{2(1)}  \\  =   - 3 +  \sqrt{14}   \: or \:  - 3 -  \sqrt{14}

8 0
1 year ago
Read 2 more answers
Convert 18 centimeters per second to meters per hour.<br> hint: 1 m = 100 cm
denis-greek [22]

Answer:

The answer to your question is 648 m/h

Step-by-step explanation:

           

                  \frac{18 cm}{s} \frac{1 m}{100 cm} \frac{3600 s}{1 h}

                  \frac{(18)(1)(3600)}{(1)(100)(1)}

                  \frac{64800}{100}

                          = 648 m/h

3 0
3 years ago
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Simplify this expression<br> x² x x x x
cupoosta [38]
Although x ² and x both have the variable x, you can’t add them together. So x + x + x + x is 4x and we just leave x ² the same. So the simplified expression is x ² + 4x. I hope this helped!!
7 0
3 years ago
he equation a = a equals StartFraction 180 left-parenthesis n minus 2 right-parenthesis Over n EndFraction. represents the angle
irina1246 [14]

Answer:

give more info ;)

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
What is the distance between the points (21 , 13) and (3 , 13) in the coordinate plane?
Oxana [17]

Answer:

\displaystyle d = 18

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (21, 13)

Point (3, 13)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(3-21)^2+(13-13)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(-18)^2+(0)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{324+0}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{324}
  5. [√Radical] Evaluate:                                                                                          \displaystyle d = 18
5 0
3 years ago
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