First one (x,y)=(0,-25/2) Second one (x,y)=(0,-26/3
Answer:
mu = x√P(x) - £
£ = x√P(x) - xP(x)
Step-by-step explanation:
We have two equations there. Laying them simultaneously, we can derive the formula for "mu" and sigma. Let sigma be "£"
Equation 1
mu = £[xP(x)]
Equation 2
£^2 = x^2 P(x) - (mu)^2
Since we have sigma raised to power 2 (that is sigma square), we find sigma by square rooting the whole equation.
Hence sigma is equal to
[x√P(x) - mu] ...(3)
Since mu = xP(x), we substitute this into equation (3) to get
Sigma = x√P(x) - xP(x)
mu = x√P(x) - £
Answer:
The numbers are -15 and 100
Step-by-step explanation:
we have
Solve the left side
so
equate the numerators and the denominators
20+x=5 ------> x=5-20=-15
100=y -------> y=5
therefore
The numbers are -15 and 100