Answer:
-21 = 6t
Step-by-step explanation:
3t - 7 = 5t
Subtract 3t from each side
3t-7-3t = 5t-3t
-7 = 2t
Multiply each side by 3 to get 6t
-7*3 = 2t*3
-21 = 6t
Answer:
7.5s
1.6666 repeating or 1.67 m/s²
Step-by-step explanation:
the equation you have to use is Vfinal=Vstart+acceleration•time
(I'm gonna simplify to Vf=Vs+at)
so you gotta rework it for the two equations
for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at
then divide acceleration on both sides to get t=(Vf–Vs)/a
for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)
so you the plug in
(I don't put the units in to the problem unless needed)
1. t=(Vf–Vs)/a to t=(0–30)/-4.0
t= -30/-4.0
t=7.5 seconds
2. a=(Vf–Vs)/t to a=(10–0)/6.0
a= 10/6.0
a= 1.67m/s²
(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)
Answer:
Step-by-step explanation:
a. when t=0,h=3ft
c.t=47/32 sec
d.
time taken to fall 2301/64 ft=0*t+\frac{1}{2}*32*t^2
t^2=\frac{2301}{64*16}
t=\frac{\sqrt{2301}}{8*4}=\frac {47.97}{32}
total ~time=\frac{47+47.97}{32}=\frac{94.97}{32} sec
Answer:
by the SAS postulate (side-angle-side)
Step-by-step explanation:
This is an overlapping triangles problem. Try drawing them separately, essentially pulling them apart. Mark side XY and XZ as congruent (given).
Angle X is shared by the two triangles, so angle X in triangle XAZ is congruent to angle A in triangle XBY.
