2 years ago

Which equation is graphed below

Mathematics

1 answer:

jeka942 years ago

3 0

Answer:

2x + 3y = 6

Step-by-step explanation:

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-12<-6x please help

pishuonlain [190]

-12 < -6x

-12/-6 > x divide both sides by -6

12/6 > x two negatives makes a positive

2 > x simplify

x < 2 switch sides

hope this helps, God bless!

6 0

3 years ago

A circle with the center at the origin and a radius length of 7

Novay_Z [31]

(7,0), (-7,0), (0,7), (0,-7)

6 0

3 years ago

Which of these choices show a pair of equivalent expressions? Check all that apply.

AleksAgata [21]

The main rule we use in this exercise is

$( \sqrt{a} ) ^{m} =( a^{ \frac{1}{2}} )^{m} = a^{ \frac{1}{2}*m}=a^{ \frac{m}{2}}$

and the more general case:

$( \sqrt[n]{a} ) ^{m} =( a^{ \frac{1}{n}} )^{m} = a^{ \frac{1}{n}*m}=a^{ \frac{m}{n}}$
Using these rules, we make all the indices, or exponents, look like $a^{ \frac{m}{n}}$ , and compare them to each other.

A. $( \sqrt{8} )^{9} = ( 8^{ \frac{1}{2}} )^{9} = 8^{ \frac{1}{2}*9}= 8^{ \frac{9}{2}}$

B. $( \sqrt{4} ) ^{5} =( 4^{ \frac{1}{2}} )^{5} = 4^{ \frac{1}{2}*5}=4^{ \frac{5}{2}}$

C. $( \sqrt[3]{125} ) ^{7} =( 125^{ \frac{1}{3}} )^{7} = 125^{ \frac{1}{3}*7}= 125^{ \frac{7}{3}}$

D. $( \sqrt{12} ) ^{7} =( 12^{ \frac{1}{2}} )^{7} = 12^{ \frac{1}{2}*7}=12^{ \frac{7}{2}}$