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Andrej [43]
3 years ago
13

If there are 30 adults at a party and 21 kids at a party what is the fraction of adults at the party

Mathematics
2 answers:
ziro4ka [17]3 years ago
5 0

Answer:

72 fraction if polygon are expectations but when you divide it it will sepetate to 70 and add the 2 angles so it would be (72)

Step-by-step explanation:

HOPE IT HELPS!!

Arisa [49]3 years ago
3 0

Answer:

i think its 70 percent maybe

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I need help with this
Sladkaya [172]

Answer:

I believe H is the answer.

Step-by-step explanation:

Double checking.

6 0
3 years ago
Divide the whole into pieces that are each ⅙ of the whole. Then, solve the equation.
yKpoI14uk [10]

Answer: 6

Explanation

If we divide our figure into six, we get the following figure:

As we can see, we are left with 6 equal parts. This can be confirmed by solving the equation:

1\div\frac{1}{6}=\frac{6}{1}=6

6 0
1 year ago
Help on this please on 16
timama [110]

Answer:

Step-by-step explanation:B

8 0
3 years ago
The length of a rectangle is twice the with. If the perimeter of the rectangle is 60 units, find the area of the garden
Darya [45]

w - width

2w - length

60 - perimeter

w + w + 2w + 2w = 6w - perimeter

The equation:

6w = 60    <em>divide both sides by 6</em>

w = 10 → 2w = 2 · 10 = 20

The area: A = width × length

A = (10)(20) = 200

<h3>Answer: The area of the garden is equal 200 square units.</h3>
4 0
3 years ago
Sin0=12/37 find tan0
alexira [117]

Answer:

\large{ \tt{❃ \: EXPLANATION}} :

  • We're provide - Sin θ = \frac{12}{37} which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = \tt{  \frac{p}{h}} ] . We're asked to find out tan θ ].

\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :

\large{ \tt{❊ \:  {h}^{2}  =  {p}^{2}  +  {b}^{2} }}

\large{ \tt{⇢ {p}^{2} +  {b}^{2}   =  {h}^{2} }}

\large{ \tt{⇢ \:  {b}^{2}  =  {h}^{2}  -  {p}^{2} }}

\large{ \tt{⇢ \:  {b}^{2} = {37}^{2} -  {12}^{2}   }}

\large{ \tt{⇢ \:  {b}^{2}  = 1369 - 144}}

\large{ \tt{ ⇢{b}^{2}  = 1225}}

\large{ \tt{⇢ \: b =  \sqrt{1225}}}

\large{ \tt{⇢ \: b = 35  \: \text {units}}}

  • Now , We know - Tan θ= \tt{ \frac{perpendicular}{base} }. Just plug the values :

\large{ \tt{➝ \: Tan  \: \theta =  \frac{p}{b}  = \boxed{ \tt{  \frac{12}{35} }}}}

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
3 years ago
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