x = 12 , y = 18 (12, 18) is the solution, intersection of the two lines.
Easy Way
100÷40=2.5 is exact middle of the integers so 20 integers are above 2.5 and 20 integers are below
22..21..20..19..18..17..16..15..14..13..12..11..10..9..8..7...6..5..4..3
2.5
2..1..0..-1..-2..-3..-4..-5..-6..-7..-8..-9..-10..-11..-12..-13..-14..-15..-16..-17..
This link will show you different equations
http://web2.0calc.com/questions/the-sum-of-40-consecutive-integers-is-100-what-is-the-smallest-of-these-40-integers
Answer:
g(f(-1)) = 48
Step-by-step explanation:
given the following
f(x) = 5x² + 2
g(x) = x²-1
g(f(x)) = g(5x²+2)
Replace x with 5x² + 2 in g(x) as shown;
g(5x²+2) = (5x²+2))²- 1
g(f(x)) = (5x²+2))²- 1
g(f(-1)) = (5(-1)²+2))²- 1
g(f(-1)) = (5+2))²- 1
g(f(-1)) = (7)²- 1
g(f(-1)) = 49 - 1
g(f(-1)) = 48
Answer: the weight of each bags are 1.85kg,
1.85kg and 3.05 kg
Step-by-step explanation:
Total weight of the three bags is
6 3/4 kg. Converting to decimal, it becomes 6.75
kg.
Two of them have the same weight. Let X
represent the bags of equal weight. Their total
weight would be 2x. The third bag is heavier
than each of the bags of equal weight by 1 1/5
kg. Converting to decimal, it becomes 1.2kg. It
means that the weight of the third bag would be
x + 1.2
Therefore, for the three bags,
2x + × + 1.2 = 6.75
3x = 6.75 - 1.2 = 5.55
x=5.55/3=1.85
Weight of the third bag is
1.85+1.2=3.05kg
5(x + 1) (3x - 8)
Hope this helps!