Find all solutions to the equation in the interval [0, 2pie]. Enter the solutions in increasing order. cos 2x = sin x
1 answer:
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Answer:
see below
Step-by-step explanation:
g(x) = (x+2)^2 -1
The function is in the form
g(x) = a(x-h)^2 +k
where (h,k) is the vertex of the parabola
Rewriting
g(x) = (x+2)^2 -1
= (x--2)^2 + -1
The vertex is (-2,-1)
We can find another point by letting x =0
g(0) = (0+2)^2 -1
=2^2 -1
=4-1 =3
The second point is (0,3)
