Question

Pls pls pls help for points

Answer 1

Answer:

see below

Step-by-step explanation:

g(x) = (x+2)^2 -1

The function is in the form

g(x) = a(x-h)^2 +k

where (h,k) is the vertex of the parabola

Rewriting

g(x) = (x+2)^2 -1

      = (x--2)^2 + -1

      The vertex is (-2,-1)

We can find another point by letting x =0

g(0) = (0+2)^2 -1

      =2^2 -1

      =4-1 =3

The second point is (0,3)

Answer 2

Answer:

Vertex: (-2,-1)

y - intercept: 3

x - intercepts: -1 and -3

Step-by-step explanation:

Vertex would be at: (-2,-1)

And the y - intercept would be 3

y = (0+2)² - 1 = 3

0 = (x+2)² - 1

(x+2)² = q

x = 1 - 2 = -1

x = -1 - 2 = -3