All categories

3 years ago

The domain of y = cot x is all real numbers such that _______.

Mathematics

1 answer:

Artyom0805 [142]3 years ago

4 0

Answer:

Step-by-step explanation:

x≠ n*π, where n is an integer

because x/π can not be an integer

You might be interested in

The graph shows the attendance at a hockey game, and the rate at which the fans enter and exit the

Strike441 [17]

Answer:

The answer is below

Step-by-step explanation:

From the graph, we can see that both segment 1 and segment 2 are positive slopes (as the time increases, the number of people increases)

Segment 1 is more steep than segment 2 (the number of people increases in segment 1 more than segment 2). This means that the number of people entering the arena in segment 1 was higher than the rate of people entering the arena in segment 2.

8 0

3 years ago

What are the coordinates of pont P on the coordinate grid below?

Shalnov [3]

Answer:

It would be (-5,3). Hope this helps!

Step-by-step explanation:

Start from zero on the x line and count until you get to the where the P is, then start from zero and count on the Y line till you get to the P.

5 0

3 years ago

How to simplify 8x2+7x-3+4x-8

Mazyrski [523]

Hello :
<span>8x²+7x-3+4x-8 = 8x² +(7x+4x) +(- 3 - 8)=8x²+7x - 11</span>

6 0

3 years ago

Graph F(x)= -3/4X + 6 plotting point

Arada [10]

Answer:

I'm not entirely sure whether is X is with 4 under the fraction or not, so I put up both graphs results.

<h3 />

First one: F(x) = -(3/4)X +6

Second graph: F(x) = -(3/4X) + 6

5 0

2 years ago

I need help with this question

Murrr4er [49]

The number of cows is given by

$14\cdot 2^{\frac{y}{5}}$

So, after $k$ years, the number of cows will be

$14\cdot 2^{\frac{y+k}{5}}$

We want this number to be twice as much as the original:

$14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})$

First of all, we can cancel 14 from both sides:

$2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}$

Finally, on the right hand side, we can use the exponent rule

$a^b\cdot a^c=a^{b+c}$

to get

$2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}$

To solve this equation, we must impose that the two exponents are the same:

$\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}$

And clearly this is true if and only if $k=5$ . So, it will take 5 years for the cow heard to double in number.

You can do the exact same steps to find the doubling time for the sheeps.

8 0

3 years ago