Z = (4y – 25° n zº 73° y = U
1 answer:
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Step 1:
First, find the total number of students.
Let the total number of students = m
Step 2:
Find the total number of students using the percentage of 4 books.
48 students listed 4 books with a percentage of 16%
Hence, there are 300 students.
a)
72 students had 1 book.
b) What percentage more read 2 books than 4 books?
percentage that read 2 books = 36%
percentage that read 4 books = 16%
36 - 16 = 20%
There are 20% students that read 2 books than 4 books.
Answer:
78.81%
Step-by-step explanation:
We are given;
Population mean; μ = 149
Sample mean; x¯ = 147.8
Sample size; n = 88
standard deviation; σ = 14
Z-score is;
z = (x¯ - μ)/(σ/√n)
Plugging in the relevant values;
z = (147.8 - 149)/(14/√88)
z = -0.804
From z-distribution table attached, we have; p = 0.21186
P(X > 147.8) = 1 - 0.21186 = 0.78814
In percentage gives; p = 78.81%
