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3 years ago

Can anyone please help me with this question on this test please I will give brainlist!!

Mathematics

2 answers:

Yanka [14]3 years ago

6 0

Answer:

they would intersect at (5,5)

aleksley [76]3 years ago

5 0

Answer:

They would intersect at 5.5,5 or take it 5,5

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PLZZ HELP ASAP MEH DUDES

Dmitrij [34]

Answer:

No solutions

Step-by-step explanation:

-3x-9=-3x-11

-3x and -3x cancel each other out

-9=-11

False

I recommend getting DESMOS graphing calculator for this sort of problem ;)

5 0

3 years ago

Read 2 more answers

MATH HELP PLZ!!!

RoseWind [281]

Answer:

a) $tan (157.5) = \frac{1-cos 315}{sin315}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos 330° = 1- 2 sin² (165°)

Step-by-step explanation:

Step(i):-

By using trigonometry formulas

cos2∝ = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ = 2 cos² ∝/2

$cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}$

cos2∝ = 1- 2 sin² ∝

cos∝ = 1- 2 sin² ∝/2

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

Step(i):-

Given

$tan\alpha = \frac{sin\alpha }{cos\alpha }$

we know that trigonometry formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

Given

$tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }$

put ∝ = 315

$tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }$

multiply with ' 2 sin (∝/2) both numerator and denominator

$tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2} }{2sin(\frac{315}{2} cos(\frac{315}{2}) }$

Apply formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

now we get

$tan (157.5) = \frac{1-cos 315}{sin315}$

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 330° above formula

$sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}$

$sin^{2} (165) = \frac{1-cos (330) }{2}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c )

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 315° above formula

$sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos∝ = 1- 2 sin² ∝/2

put ∝ = 330°

$cos 330 = 1 - 2sin^{2} (\frac{330}{2} )$

cos 330° = 1- 2 sin² (165°)

3 0

2 years ago

Can someone please help me with my homework please.p

umka2103 [35]

Answer:

8-20c

Step-by-step explanation:

Just plug 4c into the function

8-5x

8-5(4c)

8-20c

4 0

3 years ago

Find the value of x to the nearest tenth. See linked picture below. Thanks!

Ber [7]

Answer: Choice D) 11

----------------------------

Work Shown:

cos(angle) = adjacent/hypotenuse
cos(35) = 9/x
x*cos(35) = 9
x = 9/cos(35)
x = 10.9869712988531 ... make sure your calculator is in degree mode
x = 11 ... rounding to the nearest tenth

6 0

2 years ago

Which quadrilateral makes this statement true? Quadrilaterat ABCD≈____

Vinvika [58]

Answer:

FGHE

Step-by-step explanation:

They have the same angles size

6 0

2 years ago

Read 2 more answers