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3 years ago

What is the area of the figure down below

Mathematics

1 answer:

kogti [31]3 years ago

3 0

68

Explanation:

So to get this answer you need to split it into smaller shapes. We already have the squares so we know that 3*3 is 9 and then we double that because there are two of them.

So, so far we have 18+x

We need to take the middle shape and split it into two trapezoids.

The area for trapezoids is T=(a+b/2)h

So T= (3+7/2)5
T= 5*5=25
And then we would double that because there are two of them so 50 and then fill it in for x
18+50= 68 is the area of the figure.

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Answer:

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Step-by-step explanation:

Recall the mnemonics SOH CAH TOA.

SOH means the Sine ratio is Opposite over Hypotenuse.

This implies that;

$\sin A =\frac{Opposite}{Hypotenuse}$

The side opposite to angle A is 4cm and the hypotenuse is 5cm.

$\therefore \sin A =\frac{4}{5}$

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3 years ago

-8n+4(1+5n)=-6n-14 show your work

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

line will be horizontal running through (0,2)

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2 years ago

The degenerative disease osteoarthritis most frequently affects weight-bearing joints such as the knee. Two random samples from

Vinvika [58]

Answer:

$t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771$

$df=n_1 +n_2 -2=13+19-2=30$

Since is a right tailed test the p value would be:

$p_v =P(t_{30}>1.771)=0.0434$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the mean for group 1 is significantly higher than the mean for the group 2

Step-by-step explanation:

Data given

$\bar X_{1}=810$ represent the mean for sample 1

$\bar X_{2}=770$ represent the mean for sample 2

$s_{1}=67$ represent the sample standard deviation for 1

$s_{2}=56$ represent the sample standard deviation for 2

$n_{1}=13$ sample size for the group 2

$n_{2}=19$ sample size for the group 2

$\alpha=0.05$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for category 1 is higher than the mean for category 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=13+19-2=30$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(810-770)-0}{\sqrt{\frac{67^2}{13}+\frac{56^2}{19}}}}=1.771$

P value

Since is a right tailed test the p value would be:

$p_v =P(t_{30}>1.771)=0.0434$

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3 years ago

A square garden has an area of 103 square feet. . . . To the nearest tenth, what is the length of one side of the garden?. . A..

kogti [31]

A = 103 ft²;
A = l²
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l = √ 103 = 10.14889 ≈ 10.1
Answer: C ) 10.1 feet

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2 years ago

Read 2 more answers