Let's solve this system of equations through substitution.
We have these two equations.
-7x-2y=14
6x+6y=18
Now let divide the second equation by 6.
6x+6y=18 ----> x+y=3
Next, let us move y to the right side of the equation.
x+y=3 -------> x=3-y (x equals 3-y)
Because we found out that what x is in terms of y, we can input that in for every instance of x in this equation below.
-7x-2y=14 becomes -7(3-y)-2y=14 (Why? Because x equals 3-y!)
We have a one variable equation now and can solve for y.
-7(3-y)-2y=14
-21+7y-2y=14
5y=35
y=7
Plug in 7 for y in any equation to find x.
x+y=3
x+7=3
x=-4
answer: x=-4, y=7
If a quadrilateral is a rhombus then:
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,
The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units
Answer:
3
Step-by-step explanation:
Parallel lines have equal slopes, thus
line AB is parallel to line CD
Solve the equation to get values for x and y.
For example,
When x is 0,
y = 1
You have one point on the line (0,1)
Now, when y = 0,
x = 36/5 = 7.2
You have one more point on the line (7.2,0)
Plot these points on the x and y axes.
Draw a straight line joining these two points. ( I hope you can plot the points)