True or false: Sometimes older rocks end up on top of younger rocks.

Chemistry

2 answers:

olchik [2.2K]3 years ago

5 0

Answer:

true

downstream to the riverbed. However, the most common mechanism to produce older rocks on top of younger is by thrust faulting. Thrust faults form where rocks are being compressed, usually by plate tectonic mechanisms. Thrust faults rip up older strata and pile it on top of younger rocks.

Explanation:

raketka [301]3 years ago

3 0

True you’re welcome

You might be interested in

Trying to take the ged test please help me I’m stuck

JulsSmile [24]

Answer: C) Either benzene or oxygen may limit the amount of product that can be formed

Explanation: Benzene and oxygen are the reactants of the equation. What type and the amount of reactants there are in a chemical reaction affects the outcome. Therefore, seeing as benzene and oxygen are the reactants, the answer is C).

3 0

3 years ago

What makes noble gases stable?

inn [45]

The correct answer to your question is noble gases are stable due to having the maximum number of valence electrons their outer shell can hold. Meaning their outer shells are stable.

Hope this helps let me know!

8 0

3 years ago

13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What

rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

of MgCO3.3H2O in the mixture?

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

Mass water:

3.883g - 2.927g = 0.956g water

Moles water -18.01g/mol-

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

Moles MgCO3.3H2O:

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

Mass percent:

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

6 0