Answer:
please add more info into your response
Explanation:
Answer:
(B) F⁻, HCOOH
Explanation:
(A) CH₄, HCOOH
(B) F⁻, HCOOH
(C) F⁻, CH₃-O-CH₃
The hydrogen bonds are formed when the hydrogen is found between two electronegative atoms such as oxygen (O), nitrogen (N) or florine (F).
O····H-O, F····H-O, O····H-N
(A) CH₄, HCOOH
- here methane CH₄ is not capable to form hydrogen bond with water
- formic acid HCOOH can form hydrogen bonds with water
H-C(=O)-O-H····OH₂
(B) F⁻, HCOOH
-both floride (F⁻) and formic acid can form hydrogen bonds with water
F····OH₂
H-C(=O)-O-H····OH₂
(C) F⁻, CH₃-O-CH₃
- dimethyl-ether CH₃-O-CH₃ is not capable to form hydrogen bond with water
- floride (F⁻) can form hydrogen bonds with water
F····OH₂
Answer:
I think option (d) is right answer
Pb(C₂H₃O₂)₂ is lead(II) acetate
Pb(C₂H₃O₂)₂ --> Pb²⁺ + C₂H₃O₂²⁻
Lead(II) acetate ionizes in aqueous solution to form lead cation and acetate anion.
The chemical formula for the anion present in the aqueous solution of Pb(C₂H₃O₂)₂ is C₂H₃O₂²⁻
C₂H₃O₂²⁻ or CH₃COO⁻ is called the acetate ion.
Therefore, the correct answer is C₂H₃O₂²⁻
