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Levart [38]
3 years ago
12

If a solution is strongly acidic, what anionscannot be present in appreciableconcentrations?

Chemistry
1 answer:
masha68 [24]3 years ago
7 0

Explanation:

OH^- cannot be present in appreciable concentrations in a solution that is strongly acidic in nature. A weak acid is a complex that consists of hydrogen bound to an anion that does not dissociate well in solution comparing to a strong acid which dissolves completely to an anion. Therefore, OH^- cannot be present in appreciable concentrations in a solution that is strongly acidic in nature.  

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The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleane
GenaCL600 [577]

Answer : The total mass of oxygen gas released in the reaction will be, 12.8 grams

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2MgO\rightarrow 2Mg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2MgO = Total mass of 2Mg+O_2

or,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

As we are given :

Total mass of MgO = 16.12 grams

The mass of Mg = 9.72 grams

So,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

2\times 16.12g=2\times 9.72g+\text{Mass of }O_2

\text{Mass of }O_2=32.24g-19.44g=12.8g

Therefore, the total mass of oxygen gas released in the reaction will be, 12.8 grams

8 0
3 years ago
How many atoms are in 2.3 moles Au?
Vaselesa [24]

Answer:

6.02×10^23atoms of au

6 0
3 years ago
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Which statement is true about the elements in the periodic table?
s2008m [1.1K]

Answer:

Statment 2

Explanation:

This is just an educated guess

4 0
3 years ago
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4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)
Crazy boy [7]

1. The volume of ammonia consumed in the reaction is 23.2 L

2. The volume of oxygen consumed in the reaction is 29 L

<h3>Balanced equation</h3>

4NH₃(g) + 5O₂(g) --> 4NO(g) + 6H₂O(g)

From the balanced equation above,

6 L of H₂O were produced from 4 L of NH₃ and 5 L of O₂

<h3>1. How to determine the volume of ammonia, NH₃ consumed</h3>

From the balanced equation above,

6 L of H₂O were produced from 4 L of NH₃

Therefore,

34.8 L of H₂O will be produced from = (34.8 × 4) / 6 = 23.2 L of NH₃

Thus, 23.2 L of NH₃ were consumed

<h3>2. How to determine the volume of oxygen, O₂ consumed</h3>

From the balanced equation above,

6 L of H₂O were produced from 5 L of O₂

Therefore,

34.8 L of H₂O will be produced from = (34.8 × 5) / 6 = 29 L of O₂

Thus, 29 L of O₂ were consumed

Learn more about stoichiometry:

brainly.com/question/14735801

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7 0
1 year ago
How many carbon atoms are present in a 10.0g sample of C3H8
balu736 [363]

Answer:

4.09ₓ10²³ atoms are contained in 10g of C₃H₈

Explanation:

1 mol of C₃H₈ has 3 mol of carbon and 8 mol of hydrogen.

1 mol of C₃H₈ weighs 44 g

In 44 g of C₃H₈ we have 3 mol of C

In 10 g of C₃H₈ we'll have (10 . 3)/ 44 = 0.681 mol

1 mol of C has NA (6.02x10²³) particles

0.681 mol will have (0.681 . 6.02x10²³) = 4.09ₓ10²³ atoms

4 0
3 years ago
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