1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Airida [17]
4 years ago
13

(4) After addition of hydrochloric acid, a student removes the lower aqueous layer, extracts the aqueous phase with diethyl ethe

r (0.5 mL), dries the diethyl ether layer with sodium sulfate and pours the ~0.5 mL of diethyl ether into an Erlenmeyer flask, rinsing the drying agent with more diethyl ether and pouring into the flask. Upon evaporation of the diethyl ether, the student is surprised to see no crystals present to recrystallize. Assuming Parts 1–3 were completed successfully, explain where the student lost their product.
Chemistry
1 answer:
laiz [17]4 years ago
6 0

Answer:

The student did not lose any organic product in the aqueous layer

Explanation:

From the question;

After addition of hydrochloric acid, a student removes the lower aqueous layer and extracts the aqueous phase with diethyl ether (0.5 mL).

The only possible way the student could have lose the product was if there are some basic group e.g NH_2 in the compound which have a tendency of forming NH_3^+ salt.

Also these compound could be regenerated from aqueous layer by neutralizing the aqueous layer with basic solution , for example; by using sodium hydroxide (NaOH)  in which the extraction is then followed by the usage of Diethyl ether.

You might be interested in
Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {
sashaice [31]

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:

C10H15ON (aq) + H2O (l) -> C10H15ONH+ (aq) + OH- (aq)

A 0.035 M solution of ephedrine has a pH of 11.33.

a) What are the equilibrium concentrations of C10H15ON, C10H15ONH<span>+, and OH-</span>?

b) Calculate <span>Kb</span> for ephedrine.

c(C₁₀H₁₅NO) = 0,035 M.<span>
pH = 11,33.
pOH = 14 - 11,33 = 2,67.
[OH</span>⁻] = 10∧(-2,67) = 0,00213 M.<span>
[OH</span>⁻] = [C₁₀H₁₅NOH⁺] = 0,00213 M.<span>
[</span>C₁₀H₁₅NO] = 0,035 M - 0,00213 M = 0,03287 M.<span>
Kb = [OH</span>⁻] · [C₁₀H₁₅NOH⁺] / [C₁₀H₁₅NO].<span>
Kb = (</span>0,00213 M)² / 0,03287 M = 1,38·10⁻⁴.

3 0
3 years ago
A 25 kg rock is placed in a graduated cylinder with water.the volume of the fluid is 18.3ml.calculate the density of the rock in
ipn [44]

Answer:

=> 1366.120 g/mL.

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 25 Kg

Volume (v) = 18.3 mL.

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

First let's convert 25 Kg to g;

1 Kg    = 1000 g

25 Kg = ?

= \frac{25 × 1000}{1}

= 25000 g

Substitute the values into the formula:

p =  \frac{25000 g}{18.3 ml}

= 1366.120 g/mL.

Therefore, the density (rho) of the rock is  1366.120 g/mL.

8 0
2 years ago
Calculate the mass in grams, in 2.28 mol of H2SO4. Please show your work to receive credit.
solmaris [256]

Answer:

98g

Explanation:

h=1*2=2

s=32

0=16*4=64

64+32+2=98

4 0
3 years ago
A property of a particle that affects<br> how it behaves around other particles
ASHA 777 [7]

Answer:

An elementary particle can be one of two groups: a fermion or a boson. Fermions are the building blocks of matter and have mass, while bosons behave as force carriers for fermion interactions and some of them have no mass. The Standard Model is the most accepted way to explain how particles behave, and the forces that affect them. According to this model, the elementary particles are further grouped into quarks, leptons, and gauge bosons, with the Higgs boson having a special status as a non-gauge boson.

4 0
3 years ago
CH3OCH3 (ether) will dissolve in water because
dangina [55]

Answer:

a. polar solutes dissolve in polar solvents.

Explanation:

Polarity is a phenomenon that has to do with the positive and negative electric (ionic) charges of a molecule. A molecule with distinct positive and electric charge is said to be POLAR. However, water is said to be a universal solvent because it dissolves more substances than any other solvent can.

This solvent property of water is a function of its POLARITY. Polar solutes dissolve in polar solvents. Hence, only polar solutes can dissolve in water (a polar solvent). Hence, in this case, CH3OCH3 (ether) will dissolve in water because it is a POLAR molecule/solute.

5 0
3 years ago
Other questions:
  • What is the best chemistry science fair project
    8·1 answer
  • A) 2Fe(s) + O2(g) =&gt;
    11·1 answer
  • The first pesticides relied on natural chemicals, such as those taken from chrysanthemum flowers.
    8·1 answer
  • What steps are performed when naming ionic compounds?
    13·1 answer
  • Help please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    12·2 answers
  • 1
    12·1 answer
  • BRAINLIST IF U ARE CORRECT AND ANSWER ALL OF THEM!!!!!!!!!!Match the name of the way water is used to its description.
    6·2 answers
  • Hurry i only have till today to finsh this!
    8·2 answers
  • Please give me your best chemistry joke. The best joke gets Brainlest.
    8·2 answers
  • Chemical molecules that impart positional information through their concentration gradient are called
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!