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Airida [17]
3 years ago
13

(4) After addition of hydrochloric acid, a student removes the lower aqueous layer, extracts the aqueous phase with diethyl ethe

r (0.5 mL), dries the diethyl ether layer with sodium sulfate and pours the ~0.5 mL of diethyl ether into an Erlenmeyer flask, rinsing the drying agent with more diethyl ether and pouring into the flask. Upon evaporation of the diethyl ether, the student is surprised to see no crystals present to recrystallize. Assuming Parts 1–3 were completed successfully, explain where the student lost their product.
Chemistry
1 answer:
laiz [17]3 years ago
6 0

Answer:

The student did not lose any organic product in the aqueous layer

Explanation:

From the question;

After addition of hydrochloric acid, a student removes the lower aqueous layer and extracts the aqueous phase with diethyl ether (0.5 mL).

The only possible way the student could have lose the product was if there are some basic group e.g NH_2 in the compound which have a tendency of forming NH_3^+ salt.

Also these compound could be regenerated from aqueous layer by neutralizing the aqueous layer with basic solution , for example; by using sodium hydroxide (NaOH)  in which the extraction is then followed by the usage of Diethyl ether.

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Using the balanced equation below,
Zielflug [23.3K]

Answer:

Mass = 6.538 g

Explanation:

Given data:

Mass of zinc hydroxide produced = 9.65 g

Mass of zinc required = ?

Solution:

Chemical equation:

Zn + 2MnO₂ + H₂O      →      Zn(OH)₂ + Mn₂O₃

Number of moles of zinc hydroxide:

Number of moles = mass/molar mass

Number of moles = 9.65 g/ 99.42 g/mol

Number of moles = 0.1 mol

now we will compare the moles of zinc and zinc hydroxide,

                  Zn(OH)₂           :          Zn

                       1                  :          1

                    0.1                  :         0.1

Mass of zinc required:

Mass = number of moles × molar mass

Mass = 0.1 mol × 65.38 g/mol

Mass = 6.538 g

8 0
3 years ago
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Answer:

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6 0
3 years ago
Calculate the boiling temperature of a 0.50 M solution of sucrose. Assume that the concentration is 0.50 m.
Ronch [10]
There is one missing point in the question.

The formula to find an increase in boiling Temperature is :

ΔT = kb x M

ΔT = is the increase in boiling Temperature
Kb = Boiling point constant of the Solvent
M = Molarity

You did not provide the Kb. If you have it, you just have to insert it to the formula to find the ΔT.


And assuming that the other solution is water, you just have to add it up with 100 Celcius


5 0
3 years ago
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