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Airida [17]
3 years ago
13

(4) After addition of hydrochloric acid, a student removes the lower aqueous layer, extracts the aqueous phase with diethyl ethe

r (0.5 mL), dries the diethyl ether layer with sodium sulfate and pours the ~0.5 mL of diethyl ether into an Erlenmeyer flask, rinsing the drying agent with more diethyl ether and pouring into the flask. Upon evaporation of the diethyl ether, the student is surprised to see no crystals present to recrystallize. Assuming Parts 1–3 were completed successfully, explain where the student lost their product.
Chemistry
1 answer:
laiz [17]3 years ago
6 0

Answer:

The student did not lose any organic product in the aqueous layer

Explanation:

From the question;

After addition of hydrochloric acid, a student removes the lower aqueous layer and extracts the aqueous phase with diethyl ether (0.5 mL).

The only possible way the student could have lose the product was if there are some basic group e.g NH_2 in the compound which have a tendency of forming NH_3^+ salt.

Also these compound could be regenerated from aqueous layer by neutralizing the aqueous layer with basic solution , for example; by using sodium hydroxide (NaOH)  in which the extraction is then followed by the usage of Diethyl ether.

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Answer:

0.00268 M

Explanation:

To find the new molarity, you need to (1) find the moles of CuSO₄ (via the molarity equation using the beginning molarity and volume) and then (2) find the new molarity (using the moles and combined volume). Your final answer should have 3 sig figs to match the given values.

<u>Step 1:</u>

3.00 mL / 1,000 = 0.00300 L

Molarity = moles / volume (L)

0.0250 M = moles / 0.00300 L

(0.0250 M) x (0.00300 L) = moles

7.50 x 10⁻⁵ = moles

<u>Step 2:</u>

25.0 mL / 1,000 = 0.0250 L

0.0250 L + 0.00300 L = 0.0280 L

Molarity = moles / volume (L)

Molarity = (7.50 x 10⁻⁵ moles) / (0.0280 L)

Molarity = 0.00268 M

8 0
1 year ago
The viscosities of several liquids are being compared. All the liquids are poured down a slope with equal path lengths. The liqu
boyakko [2]

Explanation:

The property of a substance to resist the flow of motion is known as viscosity. And, more is the density of a substance more will be its viscosity.  

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Thus, we can conclude that the viscosities of several liquids are being compared. All the liquids are poured down a slope with equal path lengths. The liquid with the highest viscosity will reach the bottom last.

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Answer:

I Think it might be A! I hope I am right!

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The experiment that was carried out by Louisa goes to show us that different materials heat up at different rates.

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The term specific heat capacity just goes to show us the amount of heat that must be absorbed before the temperature of an object would rise by 1 K. In this case, we can see that we have been told that the after 30 minutes, the sand had heated more than the water. This simply implies that the energy that the sand and the water absorbed was able to increase the temperature of the sand mush more than it increased the temperature of the water.

Thus we can see that the heat capacity of the sand is much less than the heat capacity of the water since the sand could be able to be heated up much faster than the the water could be heated up.

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Answer:

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Explanation:

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