Answer:
it's a river flowing into the sea
Explanation:
i had it on a quiz for k12 on god it's the good one have a good day
Answer:
(A) A ball sitting on the ground
Explanation:
The answer is balanced forces
Answer:
0.382g
Explanation:
Step 1: Write the reduction half-reaction
Al³⁺(aq) + 3 e⁻ ⇒ Al(s)
Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s
We will use the following relationships.
- 1 mole of electrons has a charge of 96486 C (Faraday's constant)
- 1 mole of Al is produced when 3 moles of electrons pass through the cell.
- The molar mass of Al is 26.98 g/mol.
The mass of Al produced is:
![41.0s \times \frac{100C}{s} \times \frac{1mole^{-} }{96486C} \times \frac{1molAl}{3mole^{-} } \times \frac{26.98gAl}{1molAl} = 0.382gAl](https://tex.z-dn.net/?f=41.0s%20%5Ctimes%20%5Cfrac%7B100C%7D%7Bs%7D%20%5Ctimes%20%5Cfrac%7B1mole%5E%7B-%7D%20%7D%7B96486C%7D%20%5Ctimes%20%5Cfrac%7B1molAl%7D%7B3mole%5E%7B-%7D%20%7D%20%5Ctimes%20%5Cfrac%7B26.98gAl%7D%7B1molAl%7D%20%3D%200.382gAl)
Answer:
So a compound is 52% Zinc(Zn), 9.6% Carbon(C), and 38.4% Oxygen (O). Let’s first start off by assuming that we have 100 g of this compound. This means that we have 52 g of Zinc, 9.6 g of Carbon, and 38.4 g of Oxygen.Zinc = 65.38 g/molCarbon = 12 g/molOxygen = 16 g/molThis means we have:52 g of Zn(1 mol Zn/65.38 g of Zn) ≈0.8 mol of Zn.9.6 g of C(1 mol C/12 g of C) = 0.8 mol of C38.4 g of O(1 mol of O/16 g of O) = 2.4 mol of O.
Explanation:
What we want to do next is divide each element by the common factor of all of them, which is 0.8. In most cases, you divide each element by the element with the least amount of moles. After we divide each by 0.8, you’ll notice you have 1 Zn, 1 C, and 3 O. This gives you the empirical formula of ZnCO3, or Zinc Carbonate.