By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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Answer:
The given relation 
is a function.
Step-by-step explanation:
A relation is given.
It is required to determine whether the given relation is a function.
To determine whether the given function is a relation, identify the domain and range and then check whether the given relation is a function.
Step 1 of 1
The given relation is {(a, b),(c, d),(e, d)}.
The set of the first components of each ordered pair is called the domain.
From the relation, the domain is {a, c, e}.
The set of the second components of each ordered the range.
From the relation, the range is {b, d, d}.
The given relation is a function. But it is not a one-to-one function.
Answer:
Multiplication
Step-by-step explanation:
x=20•4
x=80
Hello.
There is only one solutin for <span> x^2 + 10x + 25 = 0
You can tell because it ends with a 0.
Have a nice day</span>
