13the pig is equal to 10
So the kinetic energy is 4
Eli lives closer to his friends house than his school
Notice the grid, the points are (-5, -2) and (4, -1), thus
![\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~{{ 4}} &,&{{ -1}}~) % (c,d) &&(~{{ -5}} &,&{{ -2}}~) \end{array}~~ % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ d=\sqrt{[-5-4]^2+[-2-(-1)]^2}\implies d=\sqrt{(-5-4)^2+(-2+1)^2} \\\\\\ d=\sqrt{(-9)^2+(-1)^2}\implies d=\sqrt{81+1}\implies d=\sqrt{82}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%26%26x_2%26%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%7B%7B%204%7D%7D%20%26%2C%26%7B%7B%20-1%7D%7D~%29%20%0A%25%20%20%28c%2Cd%29%0A%26%26%28~%7B%7B%20-5%7D%7D%20%26%2C%26%7B%7B%20-2%7D%7D~%29%0A%5Cend%7Barray%7D~~%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Csqrt%7B%5B-5-4%5D%5E2%2B%5B-2-%28-1%29%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%28-5-4%29%5E2%2B%28-2%2B1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%3D%5Csqrt%7B%28-9%29%5E2%2B%28-1%29%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B81%2B1%7D%5Cimplies%20d%3D%5Csqrt%7B82%7D)
Answer:
x=30
Step-by-step explanation:
3(x+2)^3/5 +3=27
Subtract 3 from each side
3(x+2)^3/5 +3-3=27-3
3(x+2)^3/5 =24
Divide by 3
3/3(x+2)^3/5 =24/3
(x+2)^3/5 =8
Take everything to the 5/3 power to get rid of the exponent on the left side
(x+2)^3/5 ^ 5/3=8 ^ 5/3
Remember that a^b^c = a^ (b*c)
(x+2)^(3/5 * 5/3)=8 ^ 5/3
(x+2)=8 ^ 5/3
Replace 8 with 2^3
(x+2)=2^3 ^ 5/3
Remember that a^b^c = a^ (b*c)
(x+2)=2^(3 * 5/3)
x+2 = 2^5
x+2 = 32
Subtract 2 from each side
x+2-2 = 32-2
x=30
Answer:
1394
Step-by-step explanation:
You can derive a formula for the k-th term of the sequence, but for a few terms, it is just as easy to evaluate them.
P₂₀₁₉ = 0.81(P₂₀₁₈ +25) = 0.81(2530 +25) = 2069.55
P₂₀₂₀ = 0.81(P₂₀₁₉ +25) = 0.81(2069.55 +25) = 1696.5855
P₂₀₂₁ = 0.81(P₂₀₂₀ +25) = 0.81(1696.5855 +25) ≈ 1394.48
At the start of 2021, there are predicted to be 1394 eagles in the park.
