3s is 3 times sydneys age. so the equation would be 3s-5
1. expand using place value.
337,060 = 300,000 + 30,000 + 7,000 + 000 + 60 + 0
Next, we will use exponents:
300,000 = 3 * 10^5
30,000 = 3 * 10^4
7,000 = 7 * 10^3
000 = 0 * 10^2
60 = 6 * 10
0 = 0 * 10^0
then after combing these exponents, we can write the number as:
337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 0 * 10^2 + 6 * 10 + 0 * 10^0
Finally, removing the meaningless zeroes, we would end up with:
337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 6 * 10
Answer:
a Euclidean space, the sum of angles of a triangle equals the straight angle (180 degrees, π radians, two right angles, or a half-turn). A triangle has three angles, one at each vertex, bounded by a pair of adjacent sides.
The given above may be modeled by the arithmetic sequence with initial value (I) 2200 and common difference (d) of 70. The number of applicants every year can be written by the equation,
at = a1 + (n - 1) x d
From the given above, n is equal to 4. This corresponds to the term which is 3 years from now.
at = 2200 + (4 - 1) x 70 = 2410
Thus, the enrollment capacity would be 2410 students.
Answer:
![\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
Step-by-step explanation:
We can simplify the expression under the root first.
Remember to use 
Thus, we have:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}} \\=\sqrt[4]{\frac{3x^{2}}{16y^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D%20%5C%5C%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D)
We know 4th root can be written as "to the power 1/4th". Then we can use the property 
<em>So we have:</em>
<em>![\sqrt[4]{\frac{3x^{2}}{16y^{4}}} \\=(\frac{3x^{2}}{16y^{4}})^{\frac{1}{4}}\\=\frac{3^{\frac{1}{4}}x^{\frac{1}{2}}}{2y}\\=\frac{\sqrt[4]{3x^2} }{2y}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%7D%20%5C%5C%3D%28%5Cfrac%7B3x%5E%7B2%7D%7D%7B16y%5E%7B4%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%5C%5C%3D%5Cfrac%7B3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2y%7D%5C%5C%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%20%7D%7B2y%7D)
</em>
<em />
<em>Option D is right.</em>
