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3 years ago

ASAP ASAP ASAP SHOW WORK TOO !!!!!!!!!!!!!!! thanks soo much

Mathematics

1 answer:

k0ka [10]3 years ago

4 0

A.
(64x² + 96x + 36) / (16x + 12)
= 4(16x² + 24x + 9) / 4(4x + 3)
= 4*(4x + 3)(4x + 3) / 4(4x + 3)
= 4x + 3

b.
1.79 x 10^5 = 1.79 * 100,000 = 179,000

c.
(5.9736 x 10^24) + (4.8685 x 10^24)
= (5.9736 + 4.8685) x 10^24
= 10.8421 x 10^24
= 1.08421 x 10^25

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Solve the simultaneous equations y = 2x^2 y = 3x + 14

Mekhanik [1.2K]

Answer:

x = -2

And, x = 7 ÷ 2

Step-by-step explanation:

Given that

y = 2x^2

y = 3x + 14

Now equate these two above equations

2x^2 = 3x + 14

2x^2 - 3x - 14

2x^2 -7x + 4x - 14

x(2x - 7) + 2(2x - 7)

(x + 2) (2x - 7)

So it can be x = -2

And, x = 7 ÷ 2

3 0

3 years ago

Can somebody give me the answer to this question please

Alex

the answer is either A or B, probably C, maybe D. I know it's one of those

6 0

2 years ago

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If the measure of angle A is 40 degrees and the length of side b is 15 inches, which can be the length of side a if it is possib

Julli [10]

This is the concept of trigonometry, to get the possible length of side a we use the sine rule which states that:
a/sin A=b/sin B=c/sin B
where;
a,b and c are the sides
A,B and C are the angles
thus the value of A could be as follows;
assuming the triangle is an isosceles triangle, the base angles will be:
(180-40)/2=70
thus;
15/sin 70=a/sin 40
a=(15sin40)/sin70
a=10.26 inches
thus the possible size of a=10.26 inches

8 0

3 years ago

Find the six trig function values of the angle 240*Show all work, do not use calculator

-BARSIC- [3]

Solution:

Given:

$240^0$

To get sin 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, sin 240 will be negative.

$sin240^0=sin(180+60)$

Using the trigonometric identity;

$sin(x+y)=sinx\text{ }cosy+cosx\text{ }siny$

Hence,

$\begin{gathered} sin(180+60)=sin180cos60+cos180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ sin180cos60+cos180sin60=0(\frac{1}{2})+(-1)(\frac{\sqrt{3}}{2}) \\ sin180cos60+cos180sin60=0-\frac{\sqrt{3}}{2} \\ sin180cos60+cos180sin60=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ sin240^0=-\frac{\sqrt{3}}{2} \end{gathered}$

To get cos 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, cos 240 will be negative.

$cos240^0=cos(180+60)$

Using the trigonometric identity;

$cos(x+y)=cosx\text{ }cosy-sinx\text{ }siny$

Hence,

$\begin{gathered} cos(180+60)=cos180cos60-sin180sin60 \\ sin180=0 \\ cos60=\frac{1}{2} \\ cos180=-1 \\ sin60=\frac{\sqrt{3}}{2} \\ \\ Thus, \\ cos180cos60-sin180sin60=-1(\frac{1}{2})-0(\frac{\sqrt{3}}{2}) \\ cos180cos60-sin180sin60=-\frac{1}{2}-0 \\ cos180cos60-sin180sin60=-\frac{1}{2} \\ \\ Hence, \\ cos240^0=-\frac{1}{2} \end{gathered}$

To get tan 240 degrees:

240 degrees falls in the third quadrant.

In the third quadrant, only tangent is positive. Hence, tan 240 will be positive.

$tan240^0=tan(180+60)$

Using the trigonometric identity;

$tan(180+x)=tan\text{ }x$

Hence,

$\begin{gathered} tan(180+60)=tan60 \\ tan60=\sqrt{3} \\ \\ Hence, \\ tan240^0=\sqrt{3} \end{gathered}$

To get cosec 240 degrees:

$\begin{gathered} cosec\text{ }x=\frac{1}{sinx} \\ csc240=\frac{1}{sin240} \\ sin240=-\frac{\sqrt{3}}{2} \\ \\ Hence, \\ csc240=\frac{1}{\frac{-\sqrt{3}}{2}} \\ csc240=-\frac{2}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ csc240=-\frac{2}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ csc240^0=-\frac{2\sqrt{3}}{3} \end{gathered}$

To get sec 240 degrees:

$\begin{gathered} sec\text{ }x=\frac{1}{cosx} \\ sec240=\frac{1}{cos240} \\ cos240=-\frac{1}{2} \\ \\ Hence, \\ sec240=\frac{1}{\frac{-1}{2}} \\ sec240=-2 \\ \\ Thus, \\ sec240^0=-2 \end{gathered}$

To get cot 240 degrees:

$\begin{gathered} cot\text{ }x=\frac{1}{tan\text{ }x} \\ cot240=\frac{1}{tan240} \\ tan240=\sqrt{3} \\ \\ Hence, \\ cot240=\frac{1}{\sqrt{3}} \\ \\ Rationalizing\text{ the denominator;} \\ cot240=\frac{1}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}} \\ \\ Thus, \\ cot240^0=\frac{\sqrt{3}}{3} \end{gathered}$

5 0

9 months ago

The ages of George and Genemy are in ratio 5:7 . Four years from now the ratio of their ages will be 3:4 .Find their present age

DedPeter [7]

Answer:

Below in bold.

Step-by-step explanation:

Let x be George's age and y be Genemy's age.

x/y = 5/7

(x + 4)/ (y + 4) = 3/4

From equation 1, y = 7x/5 = 1.4x so substituting in equation 2 :

(x + 4)/ (1.4x + 4) = 3/4

3(1.4x + 4) = 4(x + 4)

4.2x + 12 = 4x + 16

0.2x = 16 -12 = 4

x = 4/0.2 = 20 = George's age.

So y = 1.4x = 1.4 * 20 = 28 = Genemy's age.

3 0

3 years ago

Read 2 more answers