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Kaylis [27]
3 years ago
12

When lines are perpendicular their slopes flip and?

Mathematics
2 answers:
natka813 [3]3 years ago
8 0

Answer:

Their sign changes.

Mamont248 [21]3 years ago
7 0

For this case we have to:

Given two lines:

y_ {1} = m_ {1} x_ {1} + b_ {1}\\y_ {2} = m_ {2} x_ {2} + b_ {2}

By definition, if both lines are perpendicular to each other, then the product of their slopes is -1. That is to say:

m_ {1} * m_ {2} = - 1

ANswer:

The product of the slopes of two perpendicular lines is -1.

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Solve for kkk.
Likurg_2 [28]

Answer:

k=\frac{3}{2}

Step-by-step explanation:

Given:

\frac{k}{4}=\frac{3}{8}

To find: value of k

Solution:

Cross-multiplying is a method in which the numerator of each (or one) side is multiplied by the denominator of the other side.

\frac{k}{4}=\frac{3}{8}

On cross-multiplication, the equation becomes k\times 8=4\times 3

8k=12

Divides both sides by 8

\frac{8k}{8}=\frac{12}{8}\\k=\frac{12}{8}=\frac{3}{2}

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C. 1/6 becuase there are six numbers you could possibly land on and it is facing one side up.

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Step-by-step explanation:

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Answer:

4.69 in

Step-by-step explanation:

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\frac{ \sin \: 23 \degree}{a}  =  \frac{ \sin \: 90 \degree}{12}  \\  \\  \frac{ \sin \: 23 \degree}{a}  =  \frac{1}{12}  \\  \\ a = 12 \: \sin 23 \degree \\  \\ a = 12 \times 0.3907311285 \\  \\ a = 4.68877354 \\  \\ a \approx 4.69\: in

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3 years ago
A certain bowler can bowl a strike 85 % of the time. What is the probability that she ​a) goes three consecutive frames without
Artist 52 [7]

Answer:

a) 0.34% probability that she goes three consecutive frames without a​ strike.

b) 1.91% probability that she her first strike in the third ​frame

c) 99.66% probability that she has at least one strike in the first three ​frames.

d) 14.22% probability that she bowls a perfect game.

Step-by-step explanation:

For each frame, there are only two possible outcomes. Either there is a strike, or there is not. The probability of a strike happening in a frame is independent of other frames. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A certain bowler can bowl a strike 85 % of the time.

This means that p = 0.85

a) goes three consecutive frames without a​ strike?

This is P(X = 0) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.85)^{0}.(0.15)^{3} = 0.0034

0.34% probability that she goes three consecutive frames without a​ strike.

​b) makes her first strike in the third ​frame?

No strike during the first two(with a 15% probability)

Strike during the third(85% probability). So

P = 0.15*0.15*0.85 = 0.0191

1.91% probability that she her first strike in the third ​frame

c) has at least one strike in the first three ​frames? ​

Either there are no strikes, or there is at least one strike. The sum of the probabilities of these events is 100%.

From a), 0.34% probability that she goes three consecutive frames without a​ strike.

100 - 0.34 = 99.66

99.66% probability that she has at least one strike in the first three ​frames.

d) bowls a perfect game​ (12 consecutive​ strikes)?

This is P(X = 12) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{12,12}.(0.85)^{12}.(0.15)^{0} = 0.1422

14.22% probability that she bowls a perfect game.

3 0
4 years ago
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