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baherus [9]
2 years ago
14

by how much does the speed of a vehicle moving ina straight line change each second when it is accelerating at 2km/h/s? At 4 km/

h/s ? At 10 km /h/s?
Physics
1 answer:
Svetlanka [38]2 years ago
8 0

Answer:

At 2km/h*s it is changing speed every 2 seconds.

At 4km/h*s it is changing speed every 4 seconds.

At 10km/h*s it is changing speed every 10 seconds.

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If a 990 kg car is on the road and the Ff is 360 n what is the normal force
Veseljchak [2.6K]
Given that a car is in the road, there is only movement in the x-direction. There is no movement in the y-direction.

Looking at the y-direction for the normal force:

F = N - mg
0 = N - mg, (no movement in y-dir.)
N = mg
N = (990)(9.8)
N = 9702 newtons

The normal force exerted on the car by the road is 9702 newtons.
8 0
3 years ago
Read 2 more answers
A single-turn square loop carries a current of 16 A . The loop is 15 cm on a side and has a mass of 3.8×10^−2kg . Initially the
DiKsa [7]

Answer:

The minimum magnetic field is 0.078 T.

Explanation:

Given that,

Current = 16 A

Side = 15 cm

Mass m= 3.8\times10^{-2}\ kg

Mass each segment in given square loop is

m=\dfrac{3.8\times10^{-2}}{4}

We need to calculate the torque due to gravity

Using formula of torque

\tau_{g}=2mg(\dfrac{L}{2})+mgL

\tau_{g}=2mgL

The torque due to magnetic field

\tau_{B}=FL

\tau_{B}=BIL^2

The equilibrium condition

\tau_{B}=\tau_{g}

Put the value into the formula

BIL^2=2mgL

B=\dfrac{2mgL}{IL^2}

B=\dfrac{2mg}{IL}

Put the value into the formula

B=\dfrac{2\times\dfrac{3.8\times10^{-2}}{4}\times9.8}{16\times15\times10^{-2}}

B=0.078\ T

Hence, The minimum magnetic field is 0.078 T.

7 0
3 years ago
A book is on the table. If the weight of the book is 25 newtons, what is the magnitude and direction of the normal force?
Andrej [43]
I'm not sure about the magnitude, but the direction of the normal force is upward. 
4 0
3 years ago
Read 2 more answers
ON
mojhsa [17]

B. the distance the star is from Earth

Explanation:

The apparent magnitude of star is a function of its distance from the earth. It is one of the physical properties that is used to study a star.

The apparent magnitude of a star or other astronomical bodies is a measure of their brightness as seen from a location on the earth.

The apparent magnitude of a star depends on:

  • Distance of the star from the location on earth.
  • luminosity of the star
  • the particles along the part of the star and earth that cuts off the light the earth receives.

learn more:

Star luminosity brainly.com/question/9084808

#learnwithBrainly

5 0
3 years ago
I need help with question 6 and 7!!! Also, how to do the back???
lora16 [44]
Reword the questions and you’ll get it right
7 0
2 years ago
Read 2 more answers
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