Answer:
A compact car, with mass 725 kg, ... at 115 km/h toward the east. ... b. A second car, with a mass of 2175 kg, has the same momentum. What is its ... Glisens : m = 2175 kg;. D 21,32 xrolka. anknown. r = ? 110.6 mis east
Explanation:
It's just asking you to sit down and COUNT the little squares in each sector.
It'll help you keep everything straight if you take a very sharp pencil and make a tiny dot in each square as you count it. That way, you'll be able to see which ones you haven't counted yet, and also you won't count a square twice when you see that it already has a dot in it.
(If, by some chance, this is a picture of the orbit of a planet revolving around the sun ... as I think it might be ... then you should find that both sectors jhave the same number of squares.)
Answer: 1339.5 joules
Explanation:
Gravitational potential energy, GPE is the energy possessed by the jumper as he moves against gravity.
Thus, GPE = Mass m x Acceleration due to gravity g x Height h
Since Mass = 67kg
g = 9.8m/s^2
h = 2.04 metres
Thus, GPE = 67kg x 9.8m/s^2 x 2.04m
GPE = 1339.5 joules
Thus, the gravitational potential energy at the highest point is 1339.5 joules
Recall that average velocity is equal to change in position over a given time interval,
so that the <em>x</em>-component of 
is
and its <em>y</em>-component is
Solve for 
and 
, which are the <em>x</em>- and <em>y</em>-components of the copter's position vector after <em>t</em> = 1.60 s.
Note that I'm reading the given details as
so if any of these are incorrect, you should make the appropriate adjustments to the work above.
Answer:
Explanation:
λ = wave length = 632 x 10⁻⁹
slit width a = 2 x 10⁻³ m
angular separation of central maxima
= 2 x λ /a
= 2 x 632 x 10⁻⁹ / 2 x 10⁻³
= 632 x 10⁻⁶ rad
width in m of light spot.
= 632 x 10⁻⁶ x 376000 km
= 237.632 km
