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3 years ago

Is 12.56 greater than or less than 125.6

2 answers:

5 0

12.56 is less than 125.6 which could also be written as 12.56<125.6. 12.56 comes farther left on the number line and is of lesser value when compared to the number 125.6.

OlgaM077 [116]3 years ago

3 0

Less than .............

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(__)^2=(csc x-1)(csc x+1)

Aleksandr [31]

(csc x-1)(csc x+1)=csc²x-1²=csc²x-1=(1/sin x)² -1=1/sin x² - sin²x/sin²x=
=(1-sin²x)/sin² x = cos² x/ sin² x = (cos x/sin x)²= (cot x)²

8 0

3 years ago

Read 2 more answers

Mr. Rollosons class had a board game tournament out of 24 games played, Timeka won 10 games. Write 10 over 20 in simpliest form

Dmitry [639]

20 divided by 10 is 2
10 divided by 2 is 5 so it's 2/5

5 0

3 years ago

Find the x-intercepts for the parabola defined by the equation below. y = x2 + 9x + 14

faltersainse [42]

Answer:

x - intercepts are (-7,0) and (-2,0)

A is the correct option.

Step-by-step explanation:

We have been given the equation of the parabola $y=x^2+9x+14$

For x- intercept, y = 0

$0=x^2+9x+14$

We can split the middle term as 9x = 7x +2x

$x^2+7x+2x+14=0$

Now take GCF

$x(x+7)+2(x+7)=0$

Factored out the common term

$(x+7)(x+2)=0$

Apply the zero product property

$(x+7)=0,(x+2)=0$

Solve for x

$x=-7,-2$

Hence, x - intercepts are (-7,0) and (-2,0)

A is the correct option.

4 0

3 years ago

Caine

garri49 [273]

Answer:

well sorry I dont understand you

3 0

2 years ago

Nonlinear Systems of Equations

zheka24 [161]

The square root and cube root identities are proved.

According to the statement

we have to find that the use of the square root identity (x − y)2 = x2 − 2xy + y2

And use of cube root identity a3 + b3 = (a + b)(a2 − ab + b2).

So, For this purpose, we know that the

A. Let us assume the two conditions.

So,

2x + 3y = 6 -(1)

4x + 7y = 8 -(2)

Here we use elimination method

So, Multiply 4 with (1) and 2 with (2)

8x + 12y = 24

8x + 14y = 16

Now eliminate x from these equations

-2y = 8

here y is -4.

and the x become

2x + 3y = 6

2x -12 = 6

2x = 18

x = 9.

B. For the use of identity $(x- y)^{2} = x^{2} - 2xy + y^{2}$

Let us assume a number 26 and 28 then fill it in the condition then

$(28- 26)^{2} = 28^{2} - 2(28)(26) + 26^{2}$

Then

$(28- 26)^{2} = 784 - 1456 + 676$

$(28- 26)^{2} = 4$

And we have to prove the cube root identity then

The identity is

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

Then let us assume the number 8 and 9 then

$a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2})$

$8^{3} + 9^{3} = (8 + 9)(8^{2} - 8*9 + 9^{2})$

$8^{3} + 9^{3} = (17)(64 - 72 + 81)$

$8^{3} + 9^{3} = (17)(73)$

$8^{3} + 9^{3} = (1241)$

Hence by this way we prove the square and cube root identities.

So, The square root and cube root identities are proved.

Learn more about square root and cube root here

brainly.com/question/661780

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3 0

1 year ago