B A C ( Blood Alcohol Content ) of 0.10 means that there are 0.10 g of alcohol for every dl of blood.
5 L = 50 dl
50 * 0.10 g = 5 g
In his blood is circulating 5 grams of alcohol.
Answer:
KBr is limiting reactant.
Explanation:
Given data:
Mass of KBr =4g
Mass of Cl₂ = 6 g
Limiting reactant = ?
Solution:
Chemical equation:
2KBr + Cl₂ → 2KCl + Br₂
Number of moles of KBr:
Number of moles = mass/molar mass
Number of moles = 4 g/ 119 gmol
Number of moles = 0.03 mol
Number of moles of Cl₂:
Number of moles = mass/molar mass
Number of moles = 6 g/ 70 gmol
Number of moles = 0.09 mol
Now we will compare the moles of reactant with product.
KBr : KCl
2 : 2
0.03 : 0.03
KBr : Br₂
2 : 1
0.03 : 1/2×0.03= 0.015
Cl₂ : KCl
1 : 2
0.09 : 2/1×0.09 = 0.18
Cl₂ : Br₂
1 : 1
0.09 : 0.09
Less number of moles of product are formed by the KBr thus it will act as limiting reactant while Cl₂ is present in excess.
Answer:
a) 1.6
f)7.51
b)3.9
g)9.2
c)3.1
h)41.9
d)1.959
i)0.29
e)5.2
j)1.112
Explanation:
When you are multiplying or dividing the numbers you take the least amount of significant figures and that's how many significant figures your answer will be. Instead of being a super long answer. Hope this helps. Also, sorry it took me a hot minute :)
