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Fed [463]
3 years ago
6

How did scientists respond to Copernicus's discovery?

Chemistry
2 answers:
m_a_m_a [10]3 years ago
7 0
D.Scientist were eager to examine Copernicus evidence
Usimov [2.4K]3 years ago
5 0

Answer:

d

Explanation:

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w so do to to cm cm full do DL cl cl FLP to do cl

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Incompatibilidades do sulfato de níquel hexahidratado
nexus9112 [7]

Answer: El HEXAHIDRATO DE SULFATO DE NÍQUEL es incompatible con ácidos fuertes, azufre, Ni (NO3) 2, madera y otros combustibles. (NTP, 1992) A temperatura elevada sufre una reacción violenta con aluminio o magnesio en polvo. Cuando se calienta hasta la descomposición emite humos muy tóxicos de óxidos de azufre

Explanation:

8 0
3 years ago
Methane is a type of coal.<br> true or false
Karolina [17]
The answer is false methane is emitted from coal
3 0
3 years ago
Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:
posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of HNO_3 = \frac{15.5g}{63g/mol\times 9.5L}=0.026M

Equilibrium concentration of NO = \frac{16.6g}{30g/mol\times 9.5L}=0.058M

Equilibrium concentration of NO_2 = \frac{22.5g}{46g/mol\times 9.5L}=0.051M

Equilibrium concentration of H_2O = \frac{189.0g}{18g/mol\times 9.5L}=1.10M

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c  

For the given chemical reaction:

2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)

The expression for K_c is written as:

K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}

K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}

K_c=3.72

Thus  the value of the equilibrium constant Kc for this reaction is 3.72

5 0
3 years ago
What controls the amount of product formed in a chemical reaction
melisa1 [442]

Answer: limiting reactant controls the amount of product formed in a chemical reaction.

* Hopefully this answers your question :) Mark me the brainliest:)

~ 234483279c20~

5 0
4 years ago
If one iron nail weighs 2.0 grams, what would be the mass of 6.022 x 10^23 nails?
Maru [420]

Answer:

1.2x10^{24}g

Explanation:

Hello!

In this case, it is possible to treat this problem by using a proportional factor which indicates one iron nail equals 2.0 grams:

\frac{2.00g}{1nail}

Now, for an amount of 6.022x10²³ nails, the corresponding mass will be:

6.022x10^{23}nail*\frac{2.00g}{1nail} \\\\1.2x10^{24}g

Best regards!

8 0
3 years ago
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