Ba(MnO₄)₂ → Ba²⁺ + 2MnO₄⁻
MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O n=5
Answer:
Ni + Sn^2+ —> Sn + Ni^2+
Explanation:
First let us generate an elemental equation for the reaction. This is illustrated below:
Ni + Sn(NO3)2 —> Sn + Ni(NO3)2
From the equation above, a solid metal Sn is formed.
Now we can generate a net ionic equation as follows:
Ni + Sn^2+ —> Sn + Ni^2+
Answer:
There is 5.56 g of gold for every 1 g of chlorine
Explanation:
The question is to determine the simplest mass ratio of gold to Chlorine in the compound.
Since the mass of gold in the compound compared to chlorine is 15.39 g for every 2.77 g, the mass of gold per gram of chlorine is given as:
15.39 / 2.77 = 5.56 g of gold to two decimal places
<em>Therefore, for every 5.56 g of gold, there is 1 g of chlorine.</em>
<em>Note : The ratio in which different elements combine by mass to form a compound is given by the law of constant composition which states that, "all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.</em>
A heavily loaded truck takes more gas because it takes more power to move a heavy load.