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Nostrana [21]
3 years ago
6

The Heat of vaporization for NH3= 1360 J/g. Calculate the quantity of heat energy (in kJ)

Chemistry
1 answer:
gavmur [86]3 years ago
4 0

Answer:

Q=210.8kJ

Explanation:

Hello!

In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:

Q=m\Delta H_{vap}

In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:

Q=155g*1360J/g\\\\Q=210.8kJ

Best regards!

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Use the periodic table to select which type of bond is present and which of the listed properties is most likely for each substa
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Answer:

A = Metallic Bond

B = Strong bonding, strong conductor, high melting and boiling points

Explanation:

Since the bond is between two metals (located in groups 11 and 12), they would experience metallic bonding. Metallically bonded molecules have high melting and boiling points due to the strength of the metallic bond. They also experience strong electrical current due to the there delocalized electrons.

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"Synthesis gas" is a mixture of carbon monoxide and water vapor. At high temperature synthesis gas will form carbon dioxide and
Pavlova-9 [17]

Answer:

Check the explanation

Explanation:

Lets start by drawing the ICE chart

reaction is

...............CO + H2O ========= CO2 + H2

I.............2.6.........3.4..........................0................0

E...........1.88........2.68......................0.72............0.72

since reaction is 1 : 1 if 0.72 atm of H2 are produced then the same amount of CO2 will be formed

calculate Kp this is the relationship between the pressure of products and the pressure of reactants

Kp = Pproducts / Preactants = [Pco2* PH2] / [PCO * PH2O]

Kp = 0.72 * 0.72 / (1.88 * 2.68) = 0.1029

Write the ICE chart again

...............CO + H2O ========= CO2 + H2

I.............1.88.........2.68+1.1.................0.72................0.72

C...........-x............. -x..............................+x........................+x

E......1.88 - x...........3.78-x.....................0.72+x..... ..0.72+x

Kp is = (0.72+x)*(0.72+x) /[ (1.88-x)*(3.78-x) ] = 0.1029

lets say that x is the change of pressure.

If you solve this equation you will get a value of x equal to 0.1

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8.2x10-1 atm

6 0
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What do all of these molecules have in common?
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B they store energy.
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Which trend is observed as the first four elements in group 17 on the periodic table are considered in order of increasing atomi
ExtremeBDS [4]

ANSWER:

The melting and boiling points increase in order of increasing atomic number.

The size of the nucleus increases in order of increasing atomic number.

Ionization energy decreases in order of increasing atomic number.

Electronegativity decreases in order of increasing atomic number.

Electron Affinity decreases in order of increasing atomic number.

The reactivities decrease in order of increasing atomic number.

EXPLANATION:

NAME     MELTING POINT    BOILING POINT

Fluorine    -220              -188

Chlorine          -101                       -35

Bromine           -7.2                58.8

Iodine            114                184

Melting and Boiling points increase as shown above.

NAME     COVALENT RADIUS    IONIC RADIUS

Fluorine    71                        133

Chlorine          99                          181

Bromine           114                  196

Iodine            133                 220

Size increases as shown above.

NAME            FIRST IONIZATION ENERGY

Fluorine              1681

Chlorine             1251

Bromine              1140

Iodine               1008

Ionization energy decreases as shown above.

NAME        ELECTRONEGATIVITY

Fluorine     4

Chlorine           3

Bromine           2.8

Iodine            2.5

Electronegativity decreases as shown above.

NAME      ELECTRON AFFINITY

Fluorine    -328.0

Chlorine    -349.0

Bromine    -324.6

Iodine     -295.2

Electron affinity decreases as shown above.

REACTIVITY

The reactivities of the halogens decrease. This is due to the fact that atomic radius increases in proportion with an increase of electronic energy levels. This decreases the pull for valence electrons of other atoms, minimizing reactivity.

4 0
3 years ago
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