The Heat of vaporization for NH3= 1360 J/g. Calculate the quantity of heat energy (in kJ)
1 answer:
Answer:
Explanation:
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In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:
In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:
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Answer:
2.45Joules
Explanation:
since kinetic energy is K.E.=1/2m
lost in potential energy is gain of kinetic energy
mgh=1/2mv^2
9.8*2*0.5=v^2
=9.8
v= =3.13m/s
now k.e. = 0.5*m* =0.5*0.5*9.8 =2.45J