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Answer:
The mol fraction of cyclohexane in the liquid phase is 0.368
Explanation:
Step 1: Data given
Mass of cyclohexane = 25.0 grams
Mass of 2-methylpentane = 44.0 grams
Temperature = 35.0 °C
The pressure of cyclohexane = 150 torr
The pressure of 2-methylpentane = 313 torr
The pressure we only need for the mole fraction in gas phase.
Step 2: Calculate moles of cyclohexane
Moles cyclohexane = mass cyclohexane / molar mass
Moles cyclohexane = 25.0 g / 84 g/mol = 0.298 mol of cyclohexane
Step 3: Calculate moles of 2-methylpentane
Moles = 44.0 grams / 86 g/mol = 0.512 mol of 2-methylpentane
Step 4: Calculate mole fraction of cyclohexane in the liquid phase
Mole fraction of C6H12:
0.298 / (0.298 + 0.512) = 0.368
The mol fraction of cyclohexane in the liquid phase is 0.368
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Question:
a. Diffusion
b. Facilitated diffusion
c. Both
d. Neither
1. movement to area of lower concentration
2. movement across a membrane
3. steroid transport into cell
4. requires energy
5. movement assisted by proteins
6. glucose transport into cell
Answer:
The sorting is as follows
a. (1)
b. (5 and 6)
c. (1 and 2)
d. (4)
Explanation:
Diffusion is the movement of particles across a membrane from a high concentration region to one with a lower concentration of the diffusing substance
Here we have the correct sorting as follows
a. Diffusion
3. steroid transport into cell
b. Facilitated diffusion
5. movement assisted by proteins
6. glucose transport into cell
c. Both
1. movement to area of lower concentration
2. movement across a membrane
d. Neither
4. requires energy