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3 years ago

The Heat of vaporization for NH3= 1360 J/g. Calculate the quantity of heat energy (in kJ)

Chemistry

1 answer:

gavmur [86]3 years ago

4 0

Answer:

$Q=210.8kJ$

Explanation:

Hello!

In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:

$Q=m\Delta H_{vap}$

In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:

$Q=155g*1360J/g\\\\Q=210.8kJ$

Best regards!

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Rosa eats peanut butter sandwich for lunch. Peanut butter contains a lot of proteins, and bread is mostly starch. Rosa plan to g

Gemiola [76]

Answer:

Explanation:

This question comprises a couple of questions that are interwoven. However, the description below should suffice.

The part of the food she needs to go for the run is bread (starch) while the component of the air she requires is oxygen. This is because starch are polymers that are made of glucose monomers which are known sources of energy for the body. Air contains nitrogen, oxygen, carbon dioxide and rare gases; the oxygen from air here is necessary for many metabolic activities in the body during the race.

Her respiratory and her digestive system work together to provide her with the molecules (mainly oxygen and glucose) that she needs in her cells. The digestion of starch is a multienzyme process that is summarized as follows. The digestion of the starch (bread) begins in the mouth. The bread is acted upon by the enzyme amylase which is present in the saliva. The enzyme breaks down this starch into small glucose chains and then to dextrins and maltose (which is a disaccharide). The disaccharide is then broken down into glucose. Only a small fraction of the starch is broken down to glucose in the mouth. The broken and unbroken food substance is then taken to the stomach where little activity occur because of the acidic condition but the process continues/accelerates in the small intestine until alot of glucose is produced from the food (bread). The oxygen taken in through the respiratory system is then transported through the circulatory system to various parts of the body. The glucose molecules produced by the breakdown of starch is also diffuses into blood stream and taken up by various cells in the body.

The cells in her body convert these glucose to energy (ATP) through the process known as glycolysis (breakdown of glucose). This energy is what is released from her cells and then used to run.

3 0

3 years ago

The reform reaction between steam and gaseous methane () produces "synthesis gas," a mixture of carbon monoxide gas and dihydrog

Bond [772]

Answer:

The rate at which dihydrogen gas is being produced = 0.018 kg/s

Explanation:

Firstly, we write the balanced equation for the production of the synthesis gas

CH₄ + H₂O → CO + 3H₂

The rate of consumption of CH₄ is 159 litres per second. With the reaction ran at T = 294°C and a pressure of 0.86 atm

Using the ideal gas equation, we can convert the volumetric rate of consumption of methane to molar rate of consumption

PV = nRT

PV' = n'RT

P = pressure = 0.86 atm = 87,139.5 Pa

V' = 159 L/s = 0.159 m³/s

n' = ?

R = molar gas constant = 8.314 J/mol.K

T = absolute temperature in Kelvin = 294°C = 567.15 K

87,139.5 × 0.159 = n' × 8.314 × 567.15

n' = (87,139.5 × 0.159) ÷ (8.314 × 567.15)

n' = 2.9383547773 mol/s = 2.938 mol/s

From the stoichiometry of this reaction,

1 mole of methane gives 3 moles of dihydrogen gas

2.938 mol/s of methane will correspond to (3 × 2.938) mol/s of dihydrogen gas, that is, 8.815 mol/s.

Mass flowrate = (molar flowrate) × (molar mass)

Molar flowrate = 8.815 mol/s

Molar mass of dihydrogen gas = 2 g/mol = 0.002 kg/mol

Mass flowrate = 8.815 × 0.002 = 0.0176301287 kg/s = 0.018 kg/s to 2 s.f.

Hope this Helps!!!

3 0

4 years ago

Read 2 more answers

Which substance is an Arrhenius base?<br> (1) CH3OH (3) LiOH<br> (2) CH3Cl (4) LiCl

Nana76 [90]

According to Arrhenius Theory of acids and bases, an Arrhenius base produces OH-.

Among the four options, (3) LiOH is the correct one because it can separate into Li+ and OH- when being put in water.

Hope this helps~

7 0

3 years ago

Monosodium glutamate (NaC5H8NO4) is used extensively as a flavor enhancer what is its percent composition

tensa zangetsu [6.8K]

Answer:

% sodium= 13.6 % sodium

% carbon= 35.5 % carbon

% hydrogen= 4.7% hydrogen

% nitrogen = 8.3% nitrogen

% oxygen = 37.8 % oxygen

Explanation:

To find its percent composition means that we are to find to find the percentage of each of the constituents of the compound present.

The molar mass of monosodium glutamate is 169.11 gmol-1

Hence;

Percent of sodium= 23 gmol-1/169.11 gmol-1 × 100 = 13.6 % sodium

Percent of Carbon= 60 gmol-1/169.11 gmol-1 ×100 = 35.5 % carbon

Percent of hydrogen= 8/169.11 gmol-1 ×100 = 4.7% hydrogen

Percent nitrogen = 14/169.11 gmol-1 × 100 = 8.3% nitrogen

Percent oxygen = 64/169.11 gmol-1 ×100 = 37.8 % oxygen

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3 years ago

If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper? 1.253 g 50.72 g 79

Helen [10]

1)we need a balanced equation: CuSO₄ + Zn ---> ZnSO₄ + Cu

2) we need to convert the grams of CuSO₄ to moles using the molar mass.

molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol

$200.0 g CuSO_4 ( \frac{1 mol}{160 grams} )= 1.25 mol CuSO_4$

3) convert moles of CuSO₄ to moles of Cu

$1.25 mol CuSO_4 ( \frac{1 mol Cu}{1 mol CuSO_4} )= 1.25 mol Cu$

4) convert moles of Cu to grams using it's molar mass.

molar mass Cu= 63.5 g/mol

$1.25 mol (\frac{63.5 grams}{1 mol} )= 79.4 grams Cu$

I did it step-by-step as the explanation but you can do all of this in one step.

$200.0 g CuSO_4 ( \frac{1 mol CuSO_4}{160 g} ) ( \frac{1 mol Cu}{1 mol CuSO_4} ) ( \frac{63.5 grams}{1 mol Cu} )= 79.4 grams Cu$

4 0

4 years ago