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3 years ago

The Heat of vaporization for NH3= 1360 J/g. Calculate the quantity of heat energy (in kJ)

Chemistry

1 answer:

gavmur [86]3 years ago

4 0

Answer:

$Q=210.8kJ$

Explanation:

Hello!

In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:

$Q=m\Delta H_{vap}$

In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:

$Q=155g*1360J/g\\\\Q=210.8kJ$

Best regards!

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The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appear

djverab [1.8K]

Answer: The rate of appearance of $Br_2$ is $0.0700Ms^{-1}$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2HBr(g)\rightarrow H_2(g)+Br(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of HBr = $-\frac{1d[HBr]}{2dt}Rate in terms of appearance of [tex]H_2$ = $\frac{1d[H_2]}{dt}$

Rate in terms of appearance of $Br_2$ = $\frac{1d[Br_2]}{dt}$

$-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}$

Given :

$-\frac{1d[HBr]}{dt}=0.140Ms^{-1}$

The rate of appearance of $Br_2$ ;

$\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}$

Thus rate of appearance of $Br_2$ is $0.0700Ms^{-1}$

6 0

3 years ago

(1) In an experiment for determining the density of water, the following results

Angelina_Jolie [31]

Given parameters:

mass of an empty beaker = 65gm

mass of the beaker and water = 165gm

volume of water = 100cm³

Unknown:

Density of water = ?

Solution:

Density is the mass per unit volume of a substance;

Density = $\frac{mass}{volume}$

To find the mass of the water ;

Mass of water = Mass of beaker and water - mass of an empty beaker

= 165g - 65g

= 100g

So input parameters and solve;

Density = $\frac{100g}{100cm^{3} }$

Density of the water in the beaker = 1g/cm³

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4 years ago

Match the word with its definition.

DiKsa [7]

Mass = that which causes and object to have inertia

Newton’s First Law= a special case of Galileo’s Law of Inertia

Impulse= force multiplied by time

Momentum= velocity multiplied by mass

Velocity= momentum/mass

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7 0

4 years ago

Read 2 more answers

Determine the number of moles of the anhydrous salt present after heating, assuming that the contents of the aluminum cup after

lara31 [8.8K]

Answer:

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Explanation:

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