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drek231 [11]
4 years ago
6

How do you compare 7/8 ___ 15/16 ?

Mathematics
2 answers:
BabaBlast [244]4 years ago
6 0
7/8 < 15/16 is the correct way
solong [7]4 years ago
3 0

Answer:

7/8 < 15/16

Step-by-step explanation:

Get a common denominator of 16

7/8 *2/2

14/16

14/16 < 15/16

so 7/8 < 15/16

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6
skad [1K]

Answer:

is there a pic u could show?

Step-by-step explanation:

4 0
3 years ago
Could I get the awnser and explanation of this? Thank you!
astra-53 [7]

Answer:

equation: y = 4x-12

slope: 4

y-intercept: -12

Step-by-step explanation:

3 points across an x-axis is +1 x-axis difference and +4 y-axis away from origin, so you have to subtract 3 by 1 andsubtract y by 4. until x is 0, you get -12 on y-axis

6 0
3 years ago
The expression -310 + 15m represents a submarine that began at a depth of 310 feet below sea level and ascended at a rate of 15
Lesechka [4]

Answer:

190 feet below sea level

Step-by-step explanation:

d = -310 + 15m

d = -310 + 15(8)

d = -310 + 120

d = -190

4 0
3 years ago
Analyze the diagram below and complete the instructions that follow.<br><br> Find m
Stells [14]

Answer:

D. 70.53

Step-by-step explanation:

To solve this problem, one must use the right angle trigonometric rations. These ratios can be used to describe the ratio between the sides and an angle in a right triangle. Please note, each side is named relative to the angle that one is looking at, thus the same side can acquire different names based on the angle one uses to describe it. The trigonometric ratios are the following:

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

In this case, one is asked to find the measure of (<CBA), one is given the hypotenuse (the side opposite the right angle), and the side adjacent to this angle. Therefore, one should use the cosine (cos) function to find this angle.

cos(\theta)=\frac{adjacent}{hypotenuse}

Substitute,

cos(CBA) = \frac{3}{9}

Simplify

cos(CBA) = \frac{1}{3}

Inverse operations,

CBA=cos^-1(\frac{1}{3})

Compute,

m<CBA = 70.53

7 0
3 years ago
What is equivalent to 90/100
zysi [14]
\frac{90}{100}= \frac{\not10 *9}{\not10 *10} \\  \\  \boxed{\frac{9}{10}}
4 0
3 years ago
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