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drek231 [11]
3 years ago
6

How do you compare 7/8 ___ 15/16 ?

Mathematics
2 answers:
BabaBlast [244]3 years ago
6 0
7/8 < 15/16 is the correct way
solong [7]3 years ago
3 0

Answer:

7/8 < 15/16

Step-by-step explanation:

Get a common denominator of 16

7/8 *2/2

14/16

14/16 < 15/16

so 7/8 < 15/16

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DUE IN 5 MINUTES PLZ HELP LOL:)
katen-ka-za [31]

1) Yes

2) 5 minutes

3) 2 minutes

Step-by-step explanation:

1: Yes because, using the vertical line test, the line will cut the graph once meaning that the graph will form a function

2: 5 minutes because the horizontal line represents that she rested, therefore she was at the park for five minutes

3: 2 minutes because she traveled and reached home between 6 and 8 minutes

3 0
3 years ago
Read 2 more answers
Round 33.885 to the nearest 100th​
maria [59]

Answer:

33.89

Step-by-step explanation:

How to Calculate Rounding to the Nearest 100th?

If the digit after hundredth is greater than or equal to 5, add 1 to hundredth. Else remove the digit. Example

124.586

The third digit of right of decimal point is 6

The second digit after decimal point is 8 which is greater than 5

So add 1 to 8

Result = 124.59

6 0
2 years ago
Read 2 more answers
Hey guys i really need help pls dont waste the points i actually want help to understand how to solve equations like:
tamaranim1 [39]

Answer:

your question is unclear

Step-by-step explanation:

x+2y=4

-x -x

2y=4-x

divide by 2 to get y by it's self

y=2-(1/2x)

x+2y=4

-2y -2y

x=4-2y

i don't know if u want me to help u with the second one but i did it the first one

3 0
3 years ago
Which point lies on the line with point-slope equation y-3 = 4(x+7)?
Snowcat [4.5K]

Answer:

The answer would be (-7,3)

Step-by-step explanation:

8 0
2 years ago
Whats the equation of a line perpendicular to y= 0.25x-7 and passes through (-6,8)
-Dominant- [34]
y - 8 = 4(x + 6)
The slope perpendicular to 1/4 or .25 is 4.
Then you would use point slope form to write the equation.
Then you could simiplify the equation to y=4x+32.
8 0
3 years ago
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