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3 years ago

In a class, 60% of the students are girls. There are 18 girls in the class.

Mathematics

2 answers:

Ne4ueva [31]3 years ago

7 0

Answer:

There are 45 students and 18 boys in the class

Katarina [22]3 years ago

5 0

Answer:

a. Total of 45 students.

b. 18 Boys.

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What is 3.12 as a fraction

Vitek1552 [10]

3 3/25 is the answer..

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3 years ago

Bob has some 10lb weights and some 3lb weights. Together, all his weights add up to 50 lb. If x represents the number of 3lb wei

Leto [7]

Answer:

It is B.

Step-by-step explanation:

Because together it adds up to 50, y represents 10lb weights and x represents 3lb weights

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3 years ago

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Mike is twice as old as his sister. Together, their ages add up to 30. How old are Mike and his sister?

givi [52]

Answer:

The sister is 10 and Mike is 20

Step-by-step explanation:

10 x 2 = 20

10 +20 = 30

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2 years ago

Read 2 more answers

What is the answer???

solmaris [256]

$Method\ 2:\\\\a_n=a_{n-1}+\dfrac{1}{2}\\\\\text{It's an arithmetic sequencion where}\ a_1=-\dfrac{3}{2}\ \text{and common difference}\ d=\dfrac{1}{2}.\\\\\text{The formula of n-th term is}\ a_n=a_1+(n-1)d.\ \text{Substitute}\\\\a_n=-\dfrac{3}{2}+(n-1)\left(\dfrac{1}{2}\right)=-\dfrac{3}{2}+\dfrac{1}{2}n-\dfrac{1}{2}=-\dfrac{4}{2}+\dfrac{1}{2}n=\dfrac{1}{2}n-2\\\\a_9=\dfrac{1}{2}(9)-2=4.5-2=2.5=\dfrac{5}{2}$ $a_1=-\dfrac{3}{2}\\\\a_n=a_{n-1}+\dfrac{1}{2}\\\\Method\ 1:\\\\a_2=a_1+\dfrac{1}{2}\to a_2=-\dfrac{3}{2}+\dfrac{1}{2}=-\dfrac{2}{2}\\\\a_3=a_2+\dfraC{1}{2}\to a_3=-\dfrac{2}{2}+\dfrac{1}{2}=-\dfrac{1}{2}\\\\a_4=a_3+\dfrac{1}{2}\to a_4=-\dfrac{1}{2}+\dfrac{1}{2}=0\\\\a_5=a_4+\dfrac{1}{2}\to a_5=0+\dfrac{1}{2}=\dfrac{1}{2}\\\\a_6=a_5+\dfrac{1}{2}\to a_6=\dfrac{1}{2}+\dfrac{1}{2}=\dfrac{2}{2}\\\\a_7=a_6+\dfrac{1}{2}\to a_7=\dfrac{2}{2}+\dfrac{1}{2}=\dfrac{3}{2}$

$a_8=a_7+\dfrac{1}{2}\to a_8=\dfrac{3}{2}+\dfrac{1}{2}=\dfrac{4}{2}\\\\a_9=a_8+\dfraC{1}{2}\to a_9=\dfrac{4}{2}+\dfrac{1}{2}=\dfrac{5}{2}$

5 0

3 years ago

Can i get some help doing this plz

KATRIN_1 [288]

Answer:

The upper bound for the perimeter of the rectangle = 427.76 cm

Step-by-step explanation:

To obtain the upper bound for the perimeter, we need to first obtain the upper bound for the Length and Breadth of the rectangle.

Since, these dimensions were rounded to the nearest 1 decimal place, we can write down their ranges

Length = 127.3 cm

Width = 86.5 cm

Length can range from 127.25 cm to 127.34 cm

Breadth can range from 86.45 cm to 86.54 cm

The upper bound for the Length and Breadth of the rectangle are this 127.34 cm and 86.54 cm respectively.

Perimeter = 2 (L + B)

Upper bound of the perimeter

= 2 × (127.34 + 86.54)

= 2 × 213.88

= 427.76 cm

Hope this Helps!!!

5 0

3 years ago