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Nookie1986 [14]
2 years ago
14

IM DOING THIS IN CLASS HELP! Yesterday, there was 4 inches of snow on the ground. It snowed overnight and now there is 6 inches

of snow on the ground. What integer represents the amount of snow on the ground now
Mathematics
2 answers:
Ne4ueva [31]2 years ago
6 0

Answer:

Firstly, it was 4 inches

After snowing it becomes (4+6)= 10 inches;

From ground it is 10 inches of snow

So, <em><u>10 inches</u></em> is the right answer.

iren [92.7K]2 years ago
4 0

Answer:

6

Step-by-step explanation:

6 inches of snow is an amount above ground, so it is represented by a positive integer.

Answer: 6

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What is the distance between (-6,4) and (-8,6)? Choose 1 answer:
lukranit [14]

Answer:

D

Step-by-step explanation:

We want to find the distance between (-6, 4) and (-8, 6).

We can use the distance formula given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Let (-6, 4) be (x₁, y₁) and let (-8, 6) be (x₂, y₂).

Substitute:

d=\sqrt{(-8-(-6))^2+(6-4)^2

Evaluate:

d=\sqrt{(-2)^2+(2)^2

Evaluate:

d=\sqrt{4+4}=\sqrt{8}

Hence, our answer is D.

6 0
3 years ago
How do i solve v=pi/3*r (squared)h for h
Colt1911 [192]
V=\dfrac{\pi}{3}\cdot r^2h\ \ \ \ \ |multiply\ both\ sides\ by\ 3\\\\\pi r^2h=3V\ \ \ \ |\divide\ both\ sides\ by\ \pi r^2\\\\\boxed{h=\dfrac{3V}{\pi r^2}}
3 0
3 years ago
Given the two expressions below: 1) 4x2 − 8x + 9 2) 3x2 + 2y + 6 Is the sum of the two expressions above a polynomial? Why or wh
Mkey [24]
Sum of polynomials are always polynomials.

Note that despite it's name, single constants, monomials, binomials, trinomials, and expressions with more than three terms are all polynomials.
For example,
0, &pi; sqrt(2)x, 4x+2, x^2+3x+4, x^2-x^2, x^5+x/ &pi; -1
are all polynomials.

What makes an expression NOT a polynomial?
Expressions that contain non-integer or negative powers of variables, rational functions, infinite series.
For example,
sqrt(x+1), 1/x+4, 1+x+ x^2/2!+x^3/3!+x^4/4!+...., (5x+3)/(6x+7)
are NOT polynomials.

8 0
3 years ago
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.8 parts
Alexxandr [17]

Answer:

The value of the test statistic is t = 2.67

Step-by-step explanation:

The null hypothesis is:

H_{0} = 7.8

The alternate hypotesis is:

H_{1} \neq 7.8

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

In this problem, we have that:

X = 8.2, \mu = 7.8, \sigma = 0.6, n = 16

Then

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{8.2 - 7.8}{\frac{0.6}{\sqrt{16}}}

t = 2.67

The value of the test statistic is t = 2.67

5 0
3 years ago
PLEASE I NEED HELP URGENTLY
aleksandrvk [35]

Answer:

4.95+0.10x=120

Step-by-step explanation:

Hope this helps

5 0
3 years ago
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