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Vlada [557]
3 years ago
13

If Matrix A is 3 x 4, and Matrix B is 4 x 2, what is the size of matrix BA? If BA is undefined, please state so.

Mathematics
1 answer:
vova2212 [387]3 years ago
4 0

Answer:

Joe Mok

Step-by-step explanation:

Joe MAMA

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Its a right isosceles triangle

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2 years ago
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Explain how to graph the in inequality 8>y
insens350 [35]

Answer:

How to Graph a Linear Inequality

First, graph the "equals" line, then shade in the correct area.

There are three steps:

1.) Rearrange the equation so "y" is on the left and everything else on the right.

2.) Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

4.) Shade above the line for a "greater than" (y> or y≥)  or below the line for a "less than" (y< or y≤).

Hope This Helps!    Have A Nice Day!!

8 0
3 years ago
Solve 3 - x= -9.<br> O A. x= 6<br> O B. x= 12<br> O c. x= -6<br> O D. x=-12
Katarina [22]

Answer:

x=12

Step-by-step explanation:

you need the x alone so you substract 3 from both sides.

Then you have, -x= -12

You need the x positive so you change the sign for it but as it is an equation you need to do the same thing on the other side, making both sides positive.

x=12

6 0
2 years ago
Read 2 more answers
I need help fast...........
Gennadij [26K]
15x - 5(3x-7) = 14
15x - 15x+ 35 = 14
35 = 14 ...NOT TRUE

answer
NO solution

you got it correct
5 0
3 years ago
Two planes start flying towards each other simultaneously from two different cities. The distance between the cities is 960 mile
ANTONII [103]

Answer:

257.5 mph

332.5 mph

Step-by-step explanation:

The initial distance between the two planes is 960 miles, while the final distance (after t=1.5 h) is 75 miles, so the total distance covered by the two planes in 1.5h is

d=960-75=885 miles

Calling v1 and v2 the velocities of the two planes, we have the following equations:

(1) v_1 = v_2 + 75 --> velocity of plane 1 exceeds velocity of plane 2 by 75 mph

(2) v_1 t+ v_2 t=885 --> the total distance covered by the two planes is 885 miles (t=1.5 h is the time, and the products v1 t and v2 t represent the distance covered by each plane)

Substituting t=1.5 h, the second equation becomes:

1.5 v_1+1.5 v_2=885\\v_1 + v_2 = 590

By substituting (1) into this last equation, we find:

(v_2+75)+v_2 = 590\\2v_2 + 75 = 590\\2v_2 = 515\\v_2=257.5

And substituting this back into eq.(1), we find

v_1 = 257.5 + 75=332.5

So, the speeds of the two planes are

257.5 mph

332.5 mph



3 0
3 years ago
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