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3 years ago

Question 15

Mathematics

1 answer:

lukranit [14]3 years ago

7 0

Shejrjjsjdjejrnrnrn what is this (sorry737384 sir of

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What’s the answer ? I’m stuck

Law Incorporation [45]

Angle M equals 45°
Angle N equals 15°

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3 years ago

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

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3 years ago

city high school had a student reduction and lost 3/4 of its students. if 87 of its students were left after the reduction, how

Westkost [7]

There were 116 students originally

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The given angle is in standard position. Determine the quadrant in which the angle lies. -25°

Veronika [31]

The terminal end of the angle has dropped 25° under the x-axis.
That's Quadrant-IV .

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3 years ago

Read 2 more answers

If p-1 is a factor of p⁴+p²+p-k what is the value of k

laila [671]

Answer:

k = 3

Step-by-step explanation:

If p-1 is a factor of p⁴+p²+p-k, then we can express the polynomial in form

p⁴+p²+p-k = (p-1) * (ap³ + bp² + cp + d)

where a,b,c,d are constants. The important thing is that we can subst in p = 1 to make the polynomial zero. We can do this for original polynomial. WE must have to equal to 0 when we use p = 1 substitution...

1⁴+1²+1-k = 0

3 - k = 0

k = 3

7 0

3 years ago