Answer:
3/16
Step-by-step explanation:
1/3(1-1/4)^2
1/3(3/4)^2
1/3(9/16)
3/16
A linear approximation to the error in volume can be written as
... ∆V = (∂V/∂d)·∆d + (∂V/∂h)·∆h
For V=(π/4)·d²·h, this is
... ∆V = 2·(π/4)·d·h·∆d + (π/4)·d²·∆h
Using ∆d = 0.05d and ∆h = 0.05h, this becomes
... ∆V = (π/4)·d²·h·(2·0.05 + 0.05) = 0.15·V
The nominal volume is
... V = (π/4)·d²·h = (π/4)·(2.2 m)²·(6.8 m) = 25.849 m³
Then the maximum error in volume is
... 0.15V = 0.15·25.849 m³ ≈ 3.877 m³
_____
Essentially, the error percentage is multiplied by the exponent of the associated variable. Then these products are added to get the maximum error percentage.
B) 7 would make it true, since both 42/54 and 7/9= 0.77 repeating
Answer:
My explanation -->
Step-by-step explanation:
Go over to the left on the -4 and up 5 times and mark a dot on it.
Next, go up half a mark from 0 and put a dot there.
Then, go over to the left between the -2 and -4 and go up 5 times.
Lastly, from the 0, go down half way until the next horizontal line and place a dot there.
Outcomes in a sample space :)
