NEED HELP WILL MARK BRAINLIEST

Mathematics

1 answer:

Furkat [3]3 years ago

7 0

Answer:

Since 9 questions is 60% of the exam, you must find 100%. You could find the value of 10% by dividing 60 by 6. You do the same to 9, divide by 6 to get 1.5. Now that you have the value of 10% you can multiply 10% by 10 to get 100. You also do the same to 1.5. Your answer should be 15, if not check your work again.

Step-by-step explanation:

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Write the equation of the graph

olchik [2.2K]

Answer:

$y = 2.cos(x) - 2$

Step-by-step explanation:

1. Shifting $cos(x)$ right or left, top or down, as the graph in the question has the same illustration of $cos(x)$ . Consider

$y = a.cos(x) + b$

2. find a and b by using two sample points from the graph: $(0, 0)$ and $(\pi, -4)$

$0 = a.cos(0) + b => a + b = 0\\ -4 = a.cos(\pi) + b => b-a=-4\\\left \{ {{2b=-4} \atop {2a=4}} \right.\\a = 2, b=-2\\$

5 0

3 years ago

If perpendiculars from any point within an angle on its arms are equal, prove that it lies on the bisector of that angle

Oxana [17]

Your question can be quite confusing, but I think the gist of the question when paraphrased is: P<span>rove that the perpendiculars drawn from any point within the angle are equal if it lies on the angle bisector?

Please refer to the picture attached as a guide you through the steps of the proofs. First. construct any angle like </span>∠ABC. Next, construct an angle bisector. This is the line segment that starts from the vertex of an angle, and extends outwards such that it divides the angle into two equal parts. That would be line segment AD. Now, construct perpendicular line from the end of the angle bisector to the two other arms of the angle. This lines should form a right angle as denoted by the squares which means 90° angles. As you can see, you formed two triangles: ΔABD and ΔADC. They have congruent angles α and β as formed by the angle bisector. Then, the two right angles are also congruent. The common side AD is also congruent with respect to each of the triangles. Therefore, by Angle-Angle-Side or AAS postulate, the two triangles are congruent. That means that perpendiculars drawn from any point within the angle are equal when it lies on the angle bisector