Step-by-step explanation:
= 24 × 17 × 12
= 4,896 in³
= 12 × 10 × 4
= 480 in³
The volume of the figure
= 4,896 + 480
= 5,376 in³
"Interpret the rate of change and the y-intercept.
"
Rate of change is 5. Each ticket costs 5$.
Y-intercept is (0,-17). They spent $17 on supplies before they sold tickets.
(Sorry, you probably already know the answer)
Answer:
Step-by-step explanation:
if your question is
"Choose the student who correctly used substitution to determine if 19 was a solution to the equation. 6 + m = 24. 6 + 19 = 24. 24 = 24. 19 is a solution. 6 + m = 24. 6 + 19 = 24. 25 not-equals 24. 19 is not a solution. 6 + m = 24. 6 + 24 = 24. 30 not-equals 24. 19 is not a solution. 6 + m = 24. 6 + 19 = 24. 25 = 24. 19 is a solution."
then juan is correct
Answer:
1) No
2) Yes
Step-by-step explanation:
Given : If it took Carlos 30 minutes to cycle from his house to the library yesterday.
To find : Was the distance that he cycled greater than 6 miles?
Solution :
The relation between speed , distance and time is
![\text{Distance}=\text{Speed}\times \text{Time}](https://tex.z-dn.net/?f=%5Ctext%7BDistance%7D%3D%5Ctext%7BSpeed%7D%5Ctimes%20%5Ctext%7BTime%7D)
1) The average speed at which Carlos cycled from his house to the library yesterday was greater than 16 feet per second.
Speed = 16 feet per second
Converting into miles, ![s=\frac{16}{5280}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B16%7D%7B5280%7D)
Time = 30 minute
Converting into seconds, ![t=30\times 60](https://tex.z-dn.net/?f=t%3D30%5Ctimes%2060)
The distance he covered is
![\text{Distance}=\frac{16}{5280}\times30\times 60](https://tex.z-dn.net/?f=%5Ctext%7BDistance%7D%3D%5Cfrac%7B16%7D%7B5280%7D%5Ctimes30%5Ctimes%2060)
![\text{Distance}=5.45\text{ miles}](https://tex.z-dn.net/?f=%5Ctext%7BDistance%7D%3D5.45%5Ctext%7B%20miles%7D)
No, the distance that he cycled is not greater than 6 miles.
2) The average speed at which Carlos cycled from his house to the library yesterday was less than 18 feet per second.
Speed = 18 feet per second
Converting into miles, ![s=\frac{18}{5280}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B18%7D%7B5280%7D)
Time = 30 minute
Converting into seconds, ![t=30\times 60](https://tex.z-dn.net/?f=t%3D30%5Ctimes%2060)
The distance he covered is
![\text{Distance}=\frac{18}{5280}\times30\times 60](https://tex.z-dn.net/?f=%5Ctext%7BDistance%7D%3D%5Cfrac%7B18%7D%7B5280%7D%5Ctimes30%5Ctimes%2060)
![\text{Distance}=6.13\text{ miles}](https://tex.z-dn.net/?f=%5Ctext%7BDistance%7D%3D6.13%5Ctext%7B%20miles%7D)
Yes, the distance that he cycled is greater than 6 miles.
<span>Write an equation in the form
y
=
m
x
+
b
y=mx+b for the following table:
x y
-10 -21
-8 -15
-6 -9
-4 -3
-2 3
0 9
2 15
4 21
</span>