<span>
The rate of bullets per minute = 6000 per minute
= 6000/6 per sec
=10 bullets per sec
as we know
F=n * m * v
=10 . 200 . 25 .10^-3
= 2N</span>
After the initial push, the rock will keep moving forever at constant velocity (constant speed in a straight line)
Explanation:
We can answer this question by using Newton's first law of motion:
"An object at rest (or in motion at constant velocity) will stay at rest (or will keep moving at constant velocity) unless acted upon unbalanced forces" (Law of inertia)
In this problem, we have a rock in a place very far from any force that can act on it. This means that there are no unbalanced force acting on it, so the rock will keep its state of motion forever.
In this situation, the rock is initially thrown by the astronaut. After the initial push, which accelerates the rock up to a certain velocity, there will be no more forces acting on the rock. This means that the rock will continue moving at a constant velocity forever, so at a constant speed in a straight line.
Learn more about Newton laws of motion:
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Answer:
Explanation:
Let +y is upward direction and backward be +x direction
then we have given data
From equation simple motion we find the time
So
To get the distance between the point the package ejected to the point it the ground.
Now we have to get the distance the helicopter travels during same interval
Now to get the distance between the package and helicopter when package hit the ground
Carbon dioxide is, it is primarily emitted by machines.
Answer:
Vector angular momentum about this axis of the sphere is:
L= 3.76 kg-m²/sec
Explanation:
The formula for the moment of inertia of a sphere is:
Given:
Mass of the sphere = 13.5 kg
Radius of the sphere = 0.490 m
Thus, moment of inertia :
The expression for the angular momentum is:
L=I×ω
Given:
Angular speed(ω) = 2.9 rad/s
I, above calculated = 1.29654 kgm⁻²
Thus, angular momentum is:
L= 1.29654×2.9 kg-m²/sec
L= 3.76 kg-m²/sec
Given, the sphere is turning counterclockwise about the vertical axis. Thus, the direction of the angular momentum will be on the upper side of the plane. ( ).
Thus, angular momentum with direction is:
L= 3.76 kg-m²/sec