Answer:
Basically, it is because through probing the extreme environments of faraway massive galaxies, we can learn not only about their evolution and the history of the universe, but most importantly about the fundamental processes regulating the formation of stars.
Explanation:
Answer:
M₂ = M then L₂ = L
M₂> M then L₂ = \frac{M}{M_{2}} L
Explanation:
This is a static equilibrium exercise, to solve it we must fix a reference system at the turning point, generally in the center of the rod. By convention counterclockwise turns are considered positive
∑ τ = 0
The mass of the rock is M and placed at a distance, L the mass of the rod M₁, is considered to be placed in its center of mass, which by uniform e is in its geometric center (x = 0) and the triangular mass M₂, with a distance L₂
The triangular shape of the second object determines that its mass can be considered concentrated in its geometric center (median) that tapers with a vertical line if the triangle is equilateral, the most used shape in measurements.
M L + M₁ 0 - m₂ L₂ = 0
M L - m₂ L₂ = 0
L₂ = L
From this answer we have several possibilities
* if the two masses are equal then L₂ = L
* If the masses are different, with M₂> M then L₂ = \frac{M}{M_{2}} L
The answer is A. The kinetic energy
To increase the current and lower the voltage of the appliance to make it safe for use
Answer:
a material with a large specific heat can absorb a great deal of thermal energy without a great change in temperature.
Explanation:
The specific heat capacity of an object is the amount of energy needed to raise the temperature of 1 kg of mass of a substance by .
Mathematically, it is given by:
where
Q is the amount of energy supplied
m is the mass of the substance
is the change in temperature of the substance
The equation can be rewritten as:
Therefore, we see that the increase in temperature of a substance is inversely proportional to its specific heat capacity.
Therefore, a material with a large specific heat can absorb a great deal of thermal energy without a great change in temperature.