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3 years ago

Explain why electric discharge through a gas take place at low pressure

Physics

1 answer:

Nimfa-mama [501]3 years ago

6 0

answer:

electric discharge takes place at low pressure because a small electric field is required.

explanation:

it was found that cathode when an electric field was applied perpendicular to the length of the discharge tube the cathode rays were found to be moving in a direction opposite of electric field
credits: online

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Read 2 more answers

There are two identical, positively charged conducting spheres fixed in space. The spheres are 44.0 cm apart (center to center)

Aneli [31]

Answer:

q₁ =± 1.30 10⁻⁶ C and q₂ = ± 1.28 10⁻⁶ C

Explanation:

We will solve this problem with Coulomb's law

F = K q₁q₂ / r²

Where the Coulomb constant is value 8.99 10⁹ N m² / C²

Let's apply this equation to our problem

Case 1

F1 = k q₁ q₂ / r₁²

Where r₁ = 0.440 m and F1 = 0.0765 N

Case 2

The charges are the same

F2 = k q q / r₂²

With r₂ = r₁ = 0.440 m, the spheres are fixed and the force is F2 = 0.100 N

When the spheres are joined with the wire, the charge is distributed, distributed and matched in the two spheres

q₁ + q₂ = 2 q

Let's replace

F2 = k ½ (q₁ + q₂) / r²

Let's write the two equations and solve the system of equations

F1 = k q₁ q₂ / r²

F2 = ½ k (q₁ + q₂) / r²

F1 r² / k = (q₁ q₂)

F2 r² / k = (q₁ + q₂)/2

q₁ = 2F2 r² / k - q₂

We substitute in the other equation

F1 r² / k = (2F2 r² / k - q₂) q₂

0 = -F1 r² / k + (2F2 r² / k) q₂ - q₂²

Let's solve the second degree equation

F1 r² / K = 0.0765 0.440² / 8.99 10⁹

F1 r² / K = 1.65 10⁻¹²

(2F2 r² / k) =2 0.10 0.44² / 8.99 10⁹

(2F2 r2 / k) = 4.30 10⁻¹²

q₂² - 4.30 10⁻¹² q₂ + 1.65 10⁻¹² = 0

q₂ = ½ {4.30 10⁻¹² ± √ [(4.30 10⁻¹²)² - 4 1.65 10⁻¹²]}

q₂ = ½ {4.30 10⁻¹² ± 2,569 10⁻⁶}

q₂ = ± 1.2845 10⁻⁶ C

Now we calculate q1

F1 = k q₁ q₂ / r²

q₁ = F1 r² / (k q₂)

q₁ = 0.0765 0.440² / (8.99 10⁹ 1.2845 10⁻⁶)

q₁ = 1.30 10⁻⁶ C

3 0

3 years ago

Explain why electric discharge through a gas take place at low pressure​

Explain why electric discharge through a gas take place at low pressure