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Slav-nsk [51]
3 years ago
11

PLEASE HELP! A chemist is estimating the volume of a solution in a test tube. The actual volume of the solution is 33.4 ml. The

chemist's estimate is 35 ml.
Find the absolute error and the percent error of the chemist's estimate. If necessary, round your answers to the nearest tenth.

Mathematics
1 answer:
igomit [66]3 years ago
8 0

Absolute error is actual- estimate=33.4-35=-1.6 that in percent can be found using a rule of three, we say that 33.4 is the 100% and we find the % for -1.6

33.4ml -------- 100%

-1.8ml-----------x

x=(-1.8)(100)/33.4

x=-5.4

the percentage error is -5.4%

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3 years ago
Pls help with stats
aleksklad [387]

Answers:

  1. Exactly 25%
  2. median = 450
  3. Not enough info (see below)
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  5. IQR = 192

=========================================================

Explanations:

  1. By definition, the quartiles split the data into four equal parts. The first quartile (Q1) will have 25% of the data below it.
  2. The second quartile is the exact same value as the median. This is because the median splits the data into two equal halves, i.e. is at the midpoint.
  3. There's not enough info. We can determine that 25% of the company makes more than $60,000, but we don't know how many people total work at the company. This info is missing.
  4. Subtract the third and first quartiles (Q3 and Q1) to get the interquartile range (IQR). So IQR = Q3 - Q1 = 45-21 = 24
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2 years ago
Which postulate or theorem could be used to prove triangleLMQ is congruent to triangleLNP
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6 0
3 years ago
Read 2 more answers
Suppose y varies inversely with x, and y = 25 when x = 1/5. What is the value of y when x = 5 ?
34kurt

Answer:

y = 1

Step-by-step explanation:

Given that y varies inversely with x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = 25 when x = \frac{1}{5} , then

25 = \frac{k}{\frac{1}{5} } = 5k ( divide both sides by 5 )

5 = k

y = \frac{5}{x} ← equation of variation

When x = 5, then

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8 0
3 years ago
URGET PLEASE HELP QUICKLY
alexdok [17]

Answer: -0.5.

Step-by-step explanation:

The constant of variation k for the direct variation is given by:-

k= \dfrac{f(x_2)}{x_2}=\dfrac{f(x_1)}{x_1}

The given table:

x  f( x )

0   0

2   -1

4    -2

7   -3.5

Then,

k=\dfrac{-1}{2}=\dfrac{-2}{4}=\dfrac{7}{-3.5}=-0.5

Hence, the constant of variation k for the direct variation is -0.5.

4 0
3 years ago
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