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2 years ago

Rainfall occurs on the earth due to effect of gravity

Physics

1 answer:

Anna [14]2 years ago

3 0

<em>Answer:</em>

<em>Because </em><em>Gravity is the force of attraction between two objects, and Earth's gravity pulls matter downward, toward its center. It pulls precipitation down from clouds and pulls water downhill. Gravity also moves air and ocean water. ... Gravity pulls denser air and water downward, forcing less dense air and water to move upward.</em>

<em>Carryonlearning</em>

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The small spherical planet called "Glob" has a mass of 7.88×10^18 kg and a radius of 6.32×10^4 m. An astronaut on the surface of

Oksi-84 [34.3K]

Answer: The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down.

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Explanation: To find the answer, we need to know about the different equations of planetary motion.

<h3>How to find the initial speed of the rock as it left the astronaut's hand?</h3>

We have the expression for the initial velocity as,

$v=\sqrt{2gh}$

Thus, to find v, we have to find the acceleration due to gravity of glob. For this, we have,

$g_g=\frac{GM}{r^2} =\frac{6.67*10^{-11}*7.88*10^{18}}{(6.32*10^4)^2}= 0.132$

Now, the velocity will become,

$v=\sqrt{2*0.132*1.44*10^3} =19.46 m/s$

<h3>How to find the speed of the satellite?</h3>

As we know that, by equating both centripetal force and the gravitational force, we get the equation of speed of a satellite as,

$v=\sqrt{\frac{GM}{r} } =\sqrt{\frac{6.67*10^{-11}*7.88*10^{18}}{1.45*10^5} } =3.624km/s$

Thus, we can conclude that,

1) the initial speed of the rock as it left the astronaut's hand is 19.46 m/s.

2) A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Then the speed of the satellite is 3.624km/s.

Learn more about the equations of planetary motion here:

brainly.com/question/28108487

#SPJ4

3 0

2 years ago

Read 2 more answers

A small mass is released from rest from the edge of a frictionless, hemispherical bowl. As the mass passes through the bottom of

Greeley [361]

Answer:

$a=2g$

Explanation:

Let the radius of the hemisphere is R. The mass is released from rest so the initial speed is equal to zero and acceleration is equal to the g.

By the Newton's 3rd equation,

$v^2=u^2+2as\\v^2=2gR\\v=\sqrt{2gR}$

Now, at the bottom hemisphere the centripetal acceleration will act on the mass and the direction of this force is towards center,

$a_c=\frac{v^2}{R}\\a_c=\frac{(\sqrt{2gR} )^2}{R}\\a_c=2g$

Hence, the acceleration on the bottom of the hemisphere is equal to the 2g.

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2 years ago

Which sentence correctly describes a friction force? A. It acts in the same direction as the motion of an object. B. It acts in

KatRina [158]

Answer:

Explanation:

Friction acts in a direction opposite to the motion of an object

5 0

3 years ago

What are nasa's four great observatories and in what parts of the electromagnetic spectrum do they observe?

Hoochie [10]

1) Hubble Space Telescope- Visible and near-ultraviolet
2) Compton Gamma Ray Observatory- Gamma Rays
3) Chandra X-ray Observatory- X-rays
4) Spitzer Space Telescope- infrared

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3 years ago

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(a) You wish to determine the height of the smokestack of a local coal burning power plant. You convince a member of the mainten

kicyunya [14]

Answer:

a. 86.80 m

b. i. The mass of the bob

ii. The length of the pendulum

Explanation:

a. Determine the height of the smokestack.

Using T = 2π√(L/g) where T = period of pendulum = 18.7 s, L = length of pendulum = height of smokestack and g = acceleration due to gravity = 9.8 m/s².

So, making L subject of the formula, we have

T = 2π√(L/g)

T/2π = √(L/g)

squaring both sides, we have

(T/2π)² = L/g

L = (T/2π)²g

Substituting the values of the variables into the equation, we have

L = (T/2π)²g

L = (18.7 s/2π)²(9.8 m/s²)

L = (2.976 s)²(9.8 m/s²)

L = 8.857 s² × 9.8 m/s²

L = 86.796 m

L ≅ 86.80 m

b. What factors influence the period of a simple pendulum

The factors that influence the period of a simple pendulum are

i. The mass of the bob

ii. The length of the pendulum

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2 years ago

Rainfall occurs on the earth due to effect of gravity​

Rainfall occurs on the earth due to effect of gravity