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viktelen [127]
4 years ago
12

A Swinging Monkey A 8.72 kg monkey is hanging by one arm from a branch and swinging on a vertical circle. As an approximation, a

ssume that the radial distance between the branch and the point where the monkey's mass is located to be 84.1 cm. As it swings through the lowest point on the circle, the monkey has a speed of 2.53 m/s. Calculate the magnitude of the centripetal force acting on the monkey.
Physics
1 answer:
Readme [11.4K]4 years ago
4 0

Answer:

Centripetal force, F = 66.36 N

Explanation:

Given that,

Mass of the monkey, m = 8.72 kg

The radial distance between the branch and the point where the monkey's mass is located to be 84.1 cm, r = 84.1 cm

The speed of the monkey, v = 2.53 m/s

We need to find the  magnitude of the centripetal force acting on the monkey. It is given by :

F=\dfrac{mv^2}{r}\\\\F=\dfrac{8.72\times (2.53)^2}{84.1\times 10^{-2}}\\\\F=66.36\ N

So, the magnitude of the centripetal force acting on the monkey is 66.36 N.

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Answer:

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Disadvantage:

  1. We slip on a wet floor.
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What force must be overcome to set an object in motion
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Newtons Law of motion
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4 years ago
Suppose it takes a constant force a time of 6.0 seconds to slow a 2500 kg truck
erastovalidia [21]

Answer:

3.3\cdot 10^3\:\mathrm{N}

Explanation:

Impulse on an object is given by \mathrm{[impulse]}=F\Delta t.

However, it's also given as change in momentum (impulse-momentum theorem).

Therefore, we can set the change in momentum equal to the former formula for impulse:

\Delta p=F\Delta t.

Momentum is given by p=mv. Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:

p=2500\cdot 8.0=20,000\:\mathrm{kg\cdot m/s}.

Now we plug in our values and solve:

\Delta p=F\Delta t,\\F=\frac{\Delta p}{\Delta t},\\F=\frac{20,000}{6}=\fbox{$3.3\cdot 10^3\:\mathrm{N}$}(two significant figures).

6 0
3 years ago
Under what conditions will a moving 0.030 kg marble and a moving 2.43 kg rock have the same kinetic energy
Anestetic [448]

Answer:

To have the same kinetic energy the speed of the marble must be 9 times the speed of rock.

Explanation:

The general formula of kinetic energy is given as follows:

K.E = \frac{1}{2}mv^{2}

where,

K.E = Kinetic Energy

m = mass of the object

v = speed of the object

So, for the marble and rock to have same kinetic energy, we can write:

K.E_{marble} = K.E_{rock}\\\\\frac{1}{2}m_{marble}v_{marble}^{2} =  \frac{1}{2}m_{rock}v_{rock}^{2}\\\\(0.03\ kg)v_{marble}^{2} = (2.43\ kg)v_{rock}^{2}\\\\taking\ square\ root\ on\ both\ sides:\\v_{marble} = \sqrt{\frac{2.43\ kg}{0.03\ kg}}v_{rock}\\\\v_{marble} = 9\ v_{rock}

<u>Hence, to have the same kinetic energy the speed of the marble must be 9 times the speed of rock.</u>

4 0
3 years ago
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