2.5 miles an hour but yea hope that helps
Answer:
Part of the question is missing but here is the equation for the function;
Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.
Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3
Explanation:
What is applied is the principle of dimensional homogenuity
From the equation V = (1/3)zxt2.
- V has a dimension of [L/T]
- t has a dimension of [T]
- from the equation, make z the subject of the relation
- z = v/xt2 where 1/3 is treated as a constant
- Substituting into the equation for z
- z = L/T / L x T2
- the dimension for z = 1/T3 i.e 1/ T - raised to power 3
Answer:
Force exerted by car on truck will be 6000 N in opposite direction
Explanation:
It is given that mass of the car is one quarter of the mass of the truck
Force exerted by the truck on the car is 6000 N
We have to find the force exerted by car on the truck
According to newtons third law for any action there is equal and opposite reaction
So force exerted by car on the truck will be equal to 6000 N in opposite direction
