The resultant wave at point (5, 2) is Ψ = 5.99 cos [ 7.15 - (20/s) t]
What are the plane waves:
- A plane wave is a special case of wave or field: whose value, at any moment, is constant through any plane that is perpendicular to a fixed direction in space.
- plane waves are free-space modes.
Here,
Two plane waves are given:
c (5, t) = 4 cos [(8π/3) - (20/s) t]
c (2, t) = 2 cos [(3π/2) - (20/s) t]
now, the waves as imaginary exponentials,
separating the spatial parts, and then adding them together
we get The resultant:
Ψ = [ 4 sin (8π/3) + 2 sin (3π/2) ]^2 + [ 4 cos(8/3 π) + 2 cos(3/2π) ]^2
Ψ = 5.99 tan(a) = 0.747/ 5.95
a = 7.15
Ψ = 5.99 cos [ 7.15 - (20/s) t]
hence,
The resultant wave is Ψ = 5.99 cos [ 7.15 - (20/s) t]
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Your question is incomplete, but most probably the full question was:
Two plane waves with the same frequency and with vibrations (measured by Psi) in the z-direction are given by c (x, t) = (4cm.) cos [pi/3cm. x - 20/s t + pi] c (y, t) = (2cm.) cos[pi/4cm. y - 20/s t + pi]
Express the waves as imaginary exponentials, separate the spatial parts, and add them together using a phasor diagram to find the resultant at the point x = 5cm. y = 2cm
