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coldgirl [10]
2 years ago
5

PLEASEEEEE IM DESPITE Xd- Anyone Will mark branliest

Mathematics
2 answers:
zubka84 [21]2 years ago
8 0

Answer:

B 8.42 seconds

Step-by-step explanation:

421 in 50 seconds

421//50

8.42 seconds

Hope this helps!

kherson [118]2 years ago
6 0
Most likely B, because if you divide 421 and 50, you will get the inches per sec.
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Help me please i need some help.
Ber [7]

Answer:

2,5, 6

Step-by-step explanation:

a coefficient is the number placed before the variable in equations and the other numbers, in this case 7 and 4, are called constants

3 0
3 years ago
-4(x+3)=8 show work please
Nadusha1986 [10]

Answer:

x = -5

Step-by-step explanation:

-4(x+3)=8

(-4)(x)+(-4)(3)=8 (distribute)

-4x - 12 = 8

-4x - 12 + 12 = 8 + 12

-4x = 20

-4x/-4 = 20/-4 =

x = -5

-Elaina <3

4 0
3 years ago
Consider the equation
muminat

Answer:

A. a=10\\ \\b\neq -8

B. a=10\\ \\b= -8

Step-by-step explanation:

Consider the equation

2(5x-4) = ax + b

A. This equation has no solutions when the coefficients at x are the same and the free coefficients are not the same.

First, use distributive property:

2(5x-4)=2\cdot 5x-2\cdot 4=10x-8

So, the equation is

10x-8=ax+b

This equation has no solutions when

a=10\\ \\b\neq -8

B. The equation has infinitely many solutions when the coefficients at x are the same and the free coefficients are the same too.

So, the equation

10x-8=ax+b

has infinitely many solutions when

a=10\\ \\b= -8

In other cases, the equation has a unique solution

5 0
3 years ago
Topic 1 performance assessment pg. 53 and 54
777dan777 [17]
What are u talking about? i don't have an performance assessment of any kind 
7 0
3 years ago
Read 2 more answers
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
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